All categories

3 years ago

Find the force. 10 points. Will give brainliest!

Physics

2 answers:

zepelin [54]3 years ago

3 0

Answer:

8996kg*m/s/s

Explanation:

Given:

a=26m/s/s

m=346kg

Required:

f=?

Formula:

f=m*a

Solution:

f=346kg*26m/s/s

f=8996kg*m/s/s

Hope this helps ;) ❤❤❤

olga nikolaevna [1]3 years ago

3 0

Answer:

$\boxed{F = 8996 \ Newton}$

Explanation:

Given:

Mass = m = 346 kg

Acceleration = a = 26 m/s²

Required:

Force = F = ?

Formula:

F = ma

Solution:

F = 346 * 26

F = 8996 Newton

You might be interested in

A hiker travels 5.0 km north and then 2.5 km west What is the resultant displacement vector?

tigry1 [53]

Answer: The resultant displacement vector is 5.6km

5 0

2 years ago

Equations to use: v= λ ∙ f v=d/t

Margarita [4]

b. 460.8 m/s

Explanation:

The relationship between the speed of the wave along the string, the length of the string and the frequency of the note is

$f=\frac{v}{2L}$

where v is the speed of the wave, L is the length of the string and f is the frequency. Re-arranging the equation and substituting the data of the problem (L=0.90 m and f=256 Hz), we can find v:

$v=2Lf=2(0.90 m)(256 Hz)=460.8 m/s$

c. 18,000 m

Explanation:

The relationship between speed of the wave, distance travelled and time taken is

$v=\frac{d}{t}$

where

v = 6,000 m/s is the speed of the wave

d = ? is the distance travelled

t = 3 s is the time taken

Re-arranging the formula and substituting the numbers into it, we find:

$d=vt=(6,000 m/s)(3 s)=18,000 m$

3 0

3 years ago

A rifle is aimed horizontally at a target 47 m away. The bullet hits the target 2.3 cm below the aim point.

inna [77]

Answer:

Is your question asking for the muzzle velocity of the bullet?

Explanation:

I will assume it does

The bullet travels horizontally to the target in the same amount of time it falls 2.3 cm from vertical rest

s = ½at²

t = √(2s/g) = √(2(0.023) / 9.8) = 0.0685118...s

v = d/t = 47/0.0685118 = 686.01242...

v = 690 m/s

3 0

2 years ago

g The electric field in a sinusoidal wave changes as E =125 N>C2cos 311.2 * 1011 rad>s2t +14.2 * 102 rad>m2x] (a) In wh

joja [24]

Answer:

a) the propagation direction is x, b) E₀ = 125 N / C² , c) B = 41.67 10⁻⁸ T ,

d) f = 4.95 10¹¹ Hz, e) λ = 4.42 10⁻³ m, f) the speed of light ,

Explanation:

The equation they give for the sine wave is

E = 125 cos (14.2 10² x - 311.2 10¹¹ t)

This expression must have the general shape of a traveling wave

E = Eo cos (kx - wt + Ф)

we can equal each term between the two equations

a) the propagation direction is x, since it is the term that accompanies the vector k

b) the amplitude is the coefficient before the cosine function

E₀ = 125 N / C²

c) to find the amplitude of the magnetic field we use that the two fields are in phase

C = E / B

B = E / c

B = 125/3 10⁸

B = 41.67 10⁻⁸ T

d) the angular velocity is

w = 311.2 10¹¹ rad / s

angular velocity and frequencies are related

w = 2π f

f = w / 2π

f = 311.2 10¹¹ / 2π

f = 4.95 10¹¹ Hz

e) the wavelength is obtained from the wave number

k = 2π /λ

k = 14.2 10² rad / m

λ = 2π / k

λ = 2π / 14.2 10²

λ = 4.42 10⁻³ m

f) the speed of an electromagnetic wave is the speed of light

g) what is a transverse wave

5 0

3 years ago

A thin walled spherical shell is rolling on a surface. What

ExtremeBDS [4]

Answer:

$=\frac{1/3}{5/6} = 0.4$

Explanation:

Moment of inertia of given shell $= \frac{2}{3} MR^2$

where

M represent sphere mass

R -sphere radius

we know linear speed is given as $v = r\omega$

translational $K.E = \frac{1}{2} mv^2 = \frac{1}{2} m(r\omega)^2$

rotational $K.E = \frac{1}{2} I \omega^2 = \frac{1}{2} \frac{2}{3} MR^2 \omega^2$

total kinetic energy will be

$K.E = \frac{1}{2} m(r\omega)^2 + \frac{1}{2} \frac{2}{3} MR^2 \omega^2$

$K.E =\frac{5}{6} MR^2 \omega^2$

fraction of rotaional to total K.E

$=\frac{1/3}{5/6} = 0.4$

8 0

3 years ago