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VLD [36.1K]
3 years ago
9

01:Posttest 01:Motion Along a Straight Line

Physics
1 answer:
xenn [34]3 years ago
7 0

Answer:

D

Explanation:

Given that one rock is thrown upward at 4.5 m/s and another thrown downward at 3.4 m/s. What is the relative velocity of the first rock

from the perspective of the second rock? Assume that up is positive.

Solution.

Since both of them are moving in the opposite direction, the relative velocity of the first rock from the perspective of the second rock will be

Relative velocity = 3.4 - 4.5

Relative velocity = - 1.1 m/s

Therefore, the relative velocity from the perspective of the second rock is negative 1.1 m/s.

The correct answer is option D.

You might be interested in
Mercury has a mass of 3.3 e 23 kg and a radius of 2.44 e 6 m. Find Mercury's
valentina_108 [34]

Answer:

11.) g = 3.695 m/s^2

12.) g = 8.879 m/s^2

13.) E = 8127 N/C

Explanation:

11.) Given that the

Mercury mass M = 3.3 × 10^23kg

Radius r = 2.44 ×10^6 m

Gravitational constant G = 6.67408 × 10^-11 m3kg-1 s^-2

Gravitational field strength g can be calculated by using the formula below

g = GM/r^2

Substitutes all the parameters into the formula

g = (6.67408 × 10^-11 × 3.3 × 10^23)/(2.44×10^6)^2

g = 2.2×10^13/5.954×10^12

g = 3.695 m/s^2

12.) Given that the

Venus mass M = 4.87×10^24kg

Radius r = 6.05 × 10^6 m

Using the same formula for gravitational field strength g

g = GM/R2

Substitute all the parameters into the formula

g = (6.67408 × 10^-11 × 4.87×10^24)/(6.05×10^6)^2

g = 3.25×10^14/3.66×10^13

g = 8.879 m/s^2

13.) Given that the

Charge = 2.26 nC = 2.26×10^-9

Distance d = 0.05m

Electric field strength E can be calculated by using the formula below

E = Kq/d^2

Where

K = electrostatic constant 8.99 × 10^9 Nm2/C2

Substitutes all the parameters into the formula

E = (8.99 × 10^9 × 2.26×10^-9)/0.05^2

E = 20.3174/2.5×10^-3

E = 8126.96 N/C

7 0
4 years ago
40 POINTS
goldenfox [79]

Answer:

<em>Well, I think the best answer will be is </em><em>B) Gravity. Good luck!</em>

5 0
3 years ago
Read 2 more answers
What factors determine the distance at which two atoms form a bond ?
dsp73

Answer:

The length of the bond is determined by the number of bonded electrons (the bond order). The higher the bond order, the stronger the pull between the two atoms and the shorter the bond length. Generally, the length of the bond between two atoms is approximately the sum of the covalent radii of the two atoms.

Explanation:

4 0
3 years ago
If m1 is 50 kg and has a velocity of 4 m/s, and m2 is 75 kg and has a velocity of -1 m/s, then what would be the final velocity
MAXImum [283]

The final velocity of object 2 is: 3 m/sec

<h3>What is the conservation of mass?</h3>

According to the rule of conservation of mass, no atoms are created or destroyed during a chemical process. Instead, the atoms combine in a variety of ways to create goods. This explains why each element has the equal amount of atoms on both sides of an equation with balanced symbols.

According to conservation of mass,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Given that,

m₁ = 50 kg

m₂ = 75 kg

u₁ = 4 m/s

u₂ = -1 m/s

v₁ = -2 m/s

v₂ = ?

Now, putting the values,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(50 × 4) + [75 × (-1)] = [50 × (-2)] + (75 × v₂)

or, 125 = -100 + 75 v₂

or, 75 v₂ = 225

or, v₂ = 3 m/sec.

To know more about velocity refer to:

brainly.com/question/80295

#SPJ1

6 0
1 year ago
In the equation F = Kq1 q2/r2 solve for q2. Solve for r.
Tpy6a [65]

Answer:

r = √(k q₁ q₂ / F)

Explanation:

F = k q₁ q₂ / r²

Multiply both sides by r²:

F r² = k q₁ q₂

Divide both sides by F:

r² = k q₁ q₂ / F

Take the square root of both sides:

r = √(k q₁ q₂ / F)

3 0
3 years ago
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