Why do you think more people give importance to their body than their mind?
1 answer:
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(a) 50 rad/s
The angular speed of the CD is related to the linear speed by:
where
is the angular speed
v is the linear speed
r is the distance from the centre of the CD
When scanning the innermost part of the track, we have
v = 1.25 m/s
r = 25.0 mm = 0.025 m
Therefore, the angular speed is
(b) 21.6 rad/s
As in part a, the angular speed of the CD is given by
When scanning the outermost part of the track, we have
v = 1.25 m/s
r = 58.0 mm = 0.058 m
Therefore, the angular speed is
(c) 5550 m
The maximum playing time of the CD is
And we know that the linear speed of the track is
v = 1.25 m/s
If the track were stretched out in a straight line, then we would have a uniform motion, therefore the total length of the track would be:
(d)
The angular acceleration of the CD is given by
where
is the final angular speed (when the CD is scanned at the outermost part)
is the initial angular speed (when the CD is scanned at the innermost part)
is the time elapsed
Substituting into the equation, we find
Question is incomplete. Missing part:
Find the charge on the capacitor at the following times:
1) t = 0 mu S
2) t = 1 mu S
3) t = 50 mu S
1)
We start by calculating the initial charge on the capacitor. For this, we can use the following relationship:
where
C is the capacitance
Q0 is the initial charge stored
V0 is the initial potential difference across the capacitor
When the capacitor is connected to the battery, we have:
Solving for ,
So, when the battery is disconnected, this is the charge on the capacitor at time t = 0.
2)
To find the charge on the capacitor at any other time t, we use the equation:
where
t is the time
is the resistance
is the capacitance
Therefore, at time , we have:
3)
As before, we use again the equation:
However, here the time to consider is
Substituting into the formula,