Work is equal to force times distance times cosine of the angle between the force and the path vector making it a scalar or dot product. Work is independent of the path taken. It refers to positive change in KE or negative change in PE.
So for example if you lift a box from ground to waist height then, you did positive work over the distance you lifted it. If you pick it up to that same height, then put it back done on the ground at same place, then no work is done.
Hope this makes sense. Any questions please ask. Thank You!
Answer:

Explanation:
The figure of the problem is included below as attachment. The equations of equilibrium are presented below:



The system of equations are:


![N_{1} \cdot [(0.75\,m)-0.2\cdot (0.35\,m)] - N_{2}\cdot (1.25\,m) = 0](https://tex.z-dn.net/?f=N_%7B1%7D%20%5Ccdot%20%5B%280.75%5C%2Cm%29-0.2%5Ccdot%20%280.35%5C%2Cm%29%5D%20-%20N_%7B2%7D%5Ccdot%20%281.25%5C%2Cm%29%20%3D%200)
The solution of the system is:
,
and 
The shortest time to reach a speed of 80 km/h is:


Issac Newton
In the 17th century, Isaac Newton discovered that prisms could disassemble and reassemble white light, and described the phenomenon in his book Opticks. He was the first to use the word spectrum (Latin for "appearance" or "apparition") in this sense in print in 1671 in describing his experiments in optics.
Answer:
Will increase
Explanation:
The period of an oscillating motion is the time it takes for the system to make one complete oscillation.
The period of a spring-mass system is given by the equation:

where:
k is the spring constant
m is the mass attached to the spring
In this problem:
- The mass of the system is increased
- The spring constant is decreased
We observe that:
- The period of the system is proportional to the square root of the mass: so as the mass increases, the period will increase as well
- The period is inversely proportional to the square root of the spring constant: so as the constant decreases, the period will increase
Therefore, this means that in this case, the period will increase.
Answer:
R = V^2 sin 2 θ / g range formula
R is a maximum for θ = 45 and R = V^2 g
g = V^2 / R = 3^2 / 15 = .6 m/s^2