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3 years ago

What are the solutions to the equation?

Mathematics

2 answers:

Anika [276]3 years ago

6 0

The answer to your question is the last one through the method of competing the square

AleksandrR [38]3 years ago

6 0

Answer:

x = −10 and x = 4

Step-by-step explanation:

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Students are given 3 minutes to complete each multiple-choice question on a test and 8 minutes for each free-response question.

weqwewe [10]

Answer:

8(15-m)

Step-by-step explanation:

By looking at the options, we can understand that the right one is 8(15-m), since we need to multiply the time by the number of question.

Also, we can check that result by arranging an equations usint the total time.

55 = 3m - 8(15-m)

55 = 3m - 120 + 8m

55 = 11m - 120

55 + 120 = 11m

175 = 11m

m = 175/11 = 15.91

55 = 3*15.91 - 8(15-15.91) = 47.73 - 120 + 127.28 = 55.01 ≈ 55

6 0

3 years ago

Use the distributive property to remove the parentheses. -8(-v^[2]-3+6x^[3])

Kruka [31]

Answer:

8v^2+24-48x^3

Distribute the -8 to each term to get your answer.

Hope I helped!

6 0

3 years ago

to communication companies offer calling plans with company X it cost $0.35 to connect and then $0.05 for each minute with compa

Mama L [17]

Answer:

X Company charges $(0.2+0.01n)\times 10^2 \ cents$ more than Company Y

Step-by-step explanation:

Given:

Cost of X company = $\$ 0.35+(\$0.05\times 1 \ minute)$

Cost of Y Company = $\$ 0.15+(\$0.04\times 1 \ minute)$

for n minutes

Cost of X company for n minutes = $\$ 0.35+(\$0.05\times n \ minute)$

Cost of Y Company for n minutes = $\$ 0.15+(\$0.04\times n \ minute)$

Difference for n minutes we get by Subtracting Cost of Y Company for n minutes by Cost of X company for n minutes

Difference for n minutes = $(\$ 0.2+\$ 0.01n)$ = $(0.2+0.01n)\times 10^2 \ cents$

X Company charges $(0.2+0.01n)\times 10^2 \ cents$ more than Company Y

6 0

3 years ago

Is the real number √1.21 rational or irrational?<br> A) Rational<br> B) Irrational

AURORKA [14]

The answer is rational. It is 1.1

7 0

3 years ago

Read 2 more answers

Answer the following questions and round your answers to 2 decimal places. 84% of all Americans live in cities with population g

nignag [31]

Answer:

15.23% probability that exactly 42 of them live in cities with population greater than 50,000 people.

Step-by-step explanation:

For each American, there are only two possible outcomes. Either they live in cities with population greater than 50,000 people. Or they do not. The probability of a person living in a city with population greater than 50,000 people is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

84% of all Americans live in cities with population greater than 50,000 people.

This means that $p = 0.84$

If 50 Americans are selected at random, Find the probability that Exactly 42 of them live in cities with population greater than 50,000 people.

This is P(X = 42) when n = 50. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 42) = C_{50,42}.(0.84)^{42}.(0.16)^{8} = 0.1523$

15.23% probability that exactly 42 of them live in cities with population greater than 50,000 people.

4 0

3 years ago