All categories

3 years ago

Determine if the triangles are congruent.

Mathematics

1 answer:

xenn [34]3 years ago

8 0

Answer:

Answer to number 3:

Yes, because these two are similar triangles for sure so all their respective angles are equal in measure, and two pairs of sides are congruent to each other, so the third one must be congruent too.

You might be interested in

Find the quotient of the complex numbers. Leave answer in polar form.

Goryan [66]

$\bf \qquad \textit{division of two complex numbers}
\\\\
\cfrac{r_1[cos(\alpha)+isin(\alpha)]}{r_2[cos(\beta)+isin(\beta)]}\implies
 \cfrac{r_1}{r_2}[cos(\alpha - \beta)+isin(\alpha - \beta)]\\\\
-------------------------------$

$\bf \cfrac{z1}{z2}\implies \cfrac{\frac{1}{8}\left[cos\left(\frac{2\pi }{3} \right)+i~sin\left(\frac{2\pi }{3} \right) \right]}
{\frac{1}{3}\left[cos\left(\frac{\pi }{4} \right)+i~sin\left(\frac{\pi }{4} \right) \right]}
\\\\\\
\cfrac{\quad \frac{1}{8}\quad }{\frac{1}{3}}\left[cos\left(\frac{2\pi }{3}-\frac{\pi }{4} \right)+i~sin\left(\frac{2\pi }{3}-\frac{\pi }{4} \right) \right]
\\\\\\
\cfrac{3}{8}\left[cos\left(\frac{5\pi }{12} \right)+i~sin\left(\frac{5\pi }{12} \right) \right]$

4 0

3 years ago

What is 135 in percentage out of 100%

masya89 [10]

135 in percentage out of 100% is 1.35%
To Check This Answer
in 135(135.) move the decimal twice to the left and it becomes 1.35 you then multiply that by 100 and it will give you 135. Therefore 1.35 will become a percent which is 1.35%

5 0

4 years ago

Read 2 more answers

Given that y varies directly with x and x = 15 and y = 5 , then find what x would equal if y = 20 .

Angelina_Jolie [31]

Answer:

X=60

Step-by-step explanation:

y=kx

5=15k

k=1/3

y=1/3 x

20=1/3 x

x=60

8 0

3 years ago

Creative factor of a polynomial with the GCF a 5C.Need to write the polynomial into other

elena55 [62]

5C ( 3 + 2C)

15C + 10 C²

7 0

4 years ago

A university investigation was conducted to determine whether women and men complete medical school in significantly different a

Rudiy27

Answer:

Following are the responses to the given question:

Step-by-step explanation:

$Null \ H_{yp}: \mu_{men} = \mu_{women}\\\\Alt \ Hyp: \mu_{men} \neq \mu_{women}\\\\Std\ Error\ (SE) = \sqrt{(\frac{s_1^2}{n_1}) + (\frac{s_2^2}{n_2})} \\\\$

$= \sqrt{(\frac{0.62}{90}) + (\frac{0.52}{100})} \\\\= 0.08$

$test\ statistic \ t = \frac{(x_1 - x_2)}{SE} = \frac{(8.4 - 8.5)}{0.08} = -1.25$

Degrees of freedom

$= \frac{(\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2})^2}{\frac{(\frac{s_1^2}{n_1})^2}{(n_1 - 1)}} + \frac{(\frac{s_2^2}{n_2)^2}}{(n_2 - 1)} \\\\= 174$

Considering a degree of 5% importance

T for df critical value = 174 and sig level = 0.05 is +1.973

Let area of refusal shall be t < -1.973 or t > +1.973

Because statistical tests weren't in the refusal zone, they may not deny that zero but find that perhaps the argument how both women and men undergo med school is considerably different lengths of time is not significantly supported.

6 0

3 years ago