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snow_tiger [21]
2 years ago
10

Kory bought 2 boxes of candy and 1 soda at the movies and paid $8.00.christopher bought 1 box of candy and 1 soda and paid $5.50

. how much does 1 box of candy cost?how much does 1 soda cost? {answer with justification}
Mathematics
1 answer:
viva [34]2 years ago
4 0
Let c represent candy and s soda. 
2c+s=8
c+s=5.5
Solving the pair of simultaneous equations by eliminating s,
c=2.5
Representing the value of c in equation 1;
5+s=8
s=3
So, a box of Candy costs 2.5 and a soda costs 3

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Answer:

See answers to parts a and b below.

Step-by-step explanation:

A. Value: y=20+.20x

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B. 20+.20x=30+.10x make equations equal each other by subbing y values.

.10x=10 simplify equation

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check answers by subbing 100 for x in each equation.

y=20+.20(100)

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y=30+10

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Both equations equal 40, so 100 is the correct number of miles for when Value equals Best Rent.

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2 years ago
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Anestetic [448]

Answer:

a=10 b=30 c=20

Step-by-step explanation:

10+30=40 30+20=50 20+10=30

4 0
2 years ago
I need help on this question ASAP.
BigorU [14]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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Simplify the rational expression. State any restrictions on the variable n^4-11n^2+30/ n^4-7n^2+10
djyliett [7]
To factor both numerator and denominator in this rational expression we are going to substitute n^{2} with x; so n^{2} =x and n ^{4} =  x^{2}. This way we can rewrite the expression as follows:
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Now we have two much easier to factor expressions of the form a x^{2} +bx+c. For the numerator we need to find two numbers whose product is c (30) and its sum b (-11); those numbers are -5 and -6. (-5)(-6)=30 and -5-6=-11.
Similarly, for the denominator those numbers are -2 and -5. (-2)(-5)=10 and -2-5=-7. Now we can factor both numerator and denominator:
\frac{ x^{2} -11x+30}{ x^{2} -7x+10} = \frac{(x-6)(x-5)}{(x-2)(x-5)}
Notice that we have (x-5) in both numerator and denominator, so we can cancel those out:
\frac{x-6}{x-2}
But remember than x= n^{2}, so lets replace that to get back to our original variable:
\frac{n^{2}-6 }{n^{2}-2 }
Last but not least, the denominator of rational expression can't be zero, so the only restriction in the variable is n^{2} -2 \neq 0
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3 years ago
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Svet_ta [14]

Answer:

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