There’s nothing on the image soo
The length of the line segment SR is 15 units.
<h3>How to find the length of a line segment?</h3>
In Δ SRQ as seen in the attached image, we see that;
∠SRQ is a right angle
SQ is the hypotenuse
RT ⊥ SQ
Thus, by triangular rules, we know that;
(RQ)² = TQ × SQ
RQ = 20 units and TQ = 16 units
Thus;
(20)² = 16 × SQ
400 = 16 × SQ
SQ = 400/16
SQ = 25 units
By using Pythagoras theorem in Δ SRQ, we have;
(SR)² + (RQ)² = (SQ)²
RQ = 20 units and SQ = 25 units
Thus;
(SR)² + (20)² = (25)²
(SR)² + 400 = 625
(SR)² = 225
SR = √225
SR = 15 units
The length of the line segment SR is 15 units.
Read more about Length of Line Segment at; brainly.com/question/2437195
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To solve for the distance covered.
a) Solve for distance before applying the brake which is during the reaction time.
reaction time = 1.5 seconds, and the speed is 20m/s.
Distance = 20m/s * 1.5s = 30 m.
b) Distance covered during deceleration.
v² = u² + 2as
Deceleration, a = -7 m/s²
We would assume it decelerates to a stop. v = 0, u = 20 m/s
v² = u² + 2as
0² = 20² + 2*(-7)s
0 = 20*20 - 14s
0 = 400 - 14s
14s = 400
s = 400/14
s ≈ 28.57 m
Hence distance covered = distance covered during reaction time + distance covered during deceleration
= 30 m + 28.57 m = 58.57 m
So the car traveled ≈ 58.57 m
Hope this explains it.
Answer:
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Step-by-step explanation:
Any number. A circle of any size can be made into a square.
Hope this Helped!!! :-)