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Andrej [43]
4 years ago
15

Solve y=4x+8x for x

Mathematics
1 answer:
Semmy [17]4 years ago
5 0

Answer:

x = y/12

Step-by-step explanation:

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A square playground has a perimeter of 120 yards. What is the length of a diagonal of the playground?
Kryger [21]

We can use Pythagorean's theorem to solve this problem:

a^2 + b^2 = c^2

a and b would both be the same value, since the shape is a square.

The sides of the square would each equal 30.

30^2 = 900

a^2 = 900   which means b^2 = 900

900 + 900 = 1,800

√1,800 ≈ 42.43

A diagonal of the playground would be about 42.43 yards!

4 0
3 years ago
Which ordered pairs are on the line with equation 3x-y=2.
Juli2301 [7.4K]

The ordered pair (0 , -2) lies on the line with equation 3 x - y = 2

Step-by-step explanation:

To prove that a point lies on a line

  • Substitute x and y in the equation by the coordinates of the point
  • If the two sides of the equation equal each other, then the point lies on the line
  • If the two sides of the equation not equal each other then the point does't lie on the line

The equation of the line is 3 x - y = 2

a) Point (0 , -2)

∵ x = 0 and y = -2

- Substitute the values of x and y in the left hand side

∵ The left hand side is 3 x - y

∵ 3(0) - (-2) = 0 + 2 = 2

∴ The left hand side = 2

∵ The right hand side = 2

∴ The two sides of the equation are equal

∴ The ordered pair (0 , -2) lies on the line

b) Point (-3 , 4)

∵ x = -3 and y = 4

- Substitute the values of x and y in the left hand side

∵ The left hand side is 3 x - y

∵ 3(-3) - (4) = -9 - 4 = -13

∴ The left hand side = -13

∵ The right hand side = 2

∴ The two sides of the equation are not equal

∴ The ordered pair (-3 , 4) doesn't lie on the line

c) Point (1 , -5)

∵ x = 1 and y = -5

- Substitute the values of x and y in the left hand side

∵ The left hand side is 3 x - y

∵ 3(1) - (-5) = 3 + 5 = 8

∴ The left hand side = 8

∵ The right hand side = 2

∴ The two sides of the equation are not equal

∴ The ordered pair (1 , -5) doesn't lie on the line

The ordered pair (0 , -2) lies on the line with equation 3 x - y = 2

Learn more:

You can learn more about the linear equation in brainly.com/question/1979240

#LearnwithBrainly

4 0
4 years ago
Which of the following is a valld conclusion for the quadratic equation?
HACTEHA [7]

Answer:

x - 4 = 0 and x - 2 = 0

Step-by-step explanation:

x^2-6x+8=0\\(x-4)(x-2)=0

5 0
3 years ago
Read 2 more answers
Find the slope and Y interact from the following graph of liner liner equation
aleksandr82 [10.1K]

Answer:

A

Step-by-step explanation:

slope is rise over run 4/1 so the slope is 4 and intercept is 3.

6 0
3 years ago
A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl
lianna [129]

With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

We need to determine the slope of each side, using the formula,

m=\frac{y_2-y_1}{x_2-x_1 }

<u>Slope  of AB</u>

m_{AB}=\frac{8-5}{1--5}

\Rightarrow m_{AB}=\frac{8-5}{1+5}

\Rightarrow m_{AB}=\frac{3}{6}

\Rightarrow m_{AB}=\frac{1}{2}


<u>Slope of BC</u>

m_{BC}=\frac{2-8}{4-1}

\Rightarrow m_{BC}=\frac{-6}{3}

\Rightarrow m_{BC}=-2

<u>Slope of CD</u>

m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-4}{-6}

\Rightarrow m_{CD}=\frac{2}{3}

<u>Slope of AD</u>

m_{AD}=\frac{-2-5}{-2--5}

\Rightarrow m_{AD}=\frac{-2-5}{-2+5}

\Rightarrow m_{AD}=\frac{-7}{3}

<u>Verify Parallel sides</u>

If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

m_{AD} = \frac{-7}{3} \neq m_{BC}=-2

m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}


<u>Verify Perpendicularity</u>

And also the product of slopes of all sides with a common vertex should be -1. But

m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1

m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1


Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle




6 0
3 years ago
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