The answer is A 3x(32-19)
Reasoning: Triple the difference of 32 and 19 would be a 3x multiplication of 32-19, you need parenthesis in order to do 32-19 first because of PEMDAS. SO the answer would be 3x(32-19 because none of the other options would show the equation correctly.
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-129 is the anwser to ur problem
Addition is defined as one of the main basic operation of mathematics. Addition is also defined as the process of adding one of more numbers. For the addition operation, there are many number of properties used. In that, one of the property is known as the commutative property of addition. It states that the change of order does not change the value of addition.
Commutative property of addition is true for all types of numbers including imaginary numbers. So you can pretty much use any numbers ex.2 + 3 = 3 + 2
Answer:
1) 24 2) $2 per pencil 3) 23 4) 15 5) $5 per eraser
6) 37 7) 16 8) $16
Step-by-step explanation:
hope this helps
1. Start with ΔCIJ.
- ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
- the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
- ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.
2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So
m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.
3. Consider ΔCKL.
- ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
- ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
- the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
- ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.
4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So
m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.
5. ΔABC is isosceles, then angles adjacent to the base are congruent:
m∠KBA=m∠JAB → 222°-8x=205°-7x,
7x-8x=205°-222°,
-x=-17°,
x=17°.
Then m∠CAB=m∠CBA=205°-7x=86°.
Answer: 86°.