Complete the input/output table. Look for a pattern and write the rule

Hey um... I have a question about Cumulative frequency diagram. Its in the picture. Please help I will give you reward I promise

Mice21 [21]

Answer: see below

Step-by-step explanation:

(i)

200/2 = 100

Find 100 on cumulative frequency and the correspinding time: 14 minutes. So the answer is 14 minutes.

(ii)

First, find the lower quartile —> 200/4 = 50

Upper quartile —> 200/(3/4) = 150

Find the difference: 150 - 50 = 100

So the interquartile range is 100

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5 0

2 years ago

The third term in an arithmetic sequence is 10 and the fifth term is 26.If the first term is a1,which is an equation for the nth

dexar [7]

Just plug in 3 for n and then 5 for n to see if an turns out to be 10 and 26.

n=3:
A) an = 8*3+10 = 34
B) an = 8*3 - 14 = 10 OK
C) an = 16*3+10 = 58
D) an = 16*3 - 38 = 10 OK

n=5:
B) an = 8*5-14 = 26 OK
D) an = 16*5 - 38 = 42

So the answer is B

5 0

3 years ago

PLEASE HELP!!! I NEED HELP ASAP!!! <333

Olegator [25]

Answer:

Step-by-step explanation:

Divide: 3/13 = 3 ÷ 13

3/13 = 0.230769230769...

B) is your answer

~

6 0

2 years ago

Read 2 more answers

A leaky faucet is losing water and is filling a 8-gallon bucket every 25 hours.At this rate,how many gallons of water will the f

Angelina_Jolie [31]

The rate of 8 gallons every 25 hours means that the faucet fills $\frac{8}{25}$ gallons every hour.

Multiply the unit rate for the number of hours you're interested in to find

$\dfrac{8}{25}\cdot 13 = \dfrac{104}{25}$

6 0

3 years ago

For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10

professor190 [17]

The true statements are:

Tyson's expression is not equivalent to the original expression
The equivalent expression is: $\frac{1}{2}g- \frac 1{5}$

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}$

Collect like terms

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10} -\frac{1}{10}$

Evaluate the like terms

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}$

Tyler's equivalent expression is given as:

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}$

Collect like terms

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}$

Evaluate the like terms

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g$

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0

2 years ago