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lord [1]
3 years ago
9

Complete the input/output table. Look for a pattern and write the rule

Mathematics
1 answer:
Ivenika [448]3 years ago
6 0

the rule is look for the same number.
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Hey um... I have a question about Cumulative frequency diagram. Its in the picture. Please help I will give you reward I promise
Mice21 [21]

Answer: see below

Step-by-step explanation:

(i)

200/2 = 100

Find 100 on cumulative frequency and the correspinding time: 14 minutes. So the answer is 14 minutes.

(ii)

First, find the lower quartile —> 200/4 = 50

Upper quartile —> 200/(3/4) = 150

Find the difference: 150 - 50 = 100

So the interquartile range is 100

For detailed, step-by-step explanations you can visit my fiverr account: kesja_

I provide detailed explanations for math questions for as little as $1!

5 0
2 years ago
The third term in an arithmetic sequence is 10 and the fifth term is 26.If the first term is a1,which is an equation for the nth
dexar [7]
Just plug in 3 for n and then 5 for n to see if an turns out to be 10 and 26.

n=3:
A) an = 8*3+10 = 34
B) an = 8*3 - 14 = 10  OK
C) an = 16*3+10 = 58
D) an = 16*3 - 38 = 10 OK

n=5:
B) an = 8*5-14 = 26 OK
D) an = 16*5 - 38 = 42

So the answer is B
5 0
3 years ago
PLEASE HELP!!! I NEED HELP ASAP!!! <333
Olegator [25]

Answer:

Step-by-step explanation:

Divide: 3/13 = 3 ÷ 13

3/13 = 0.230769230769...

B) is your answer

~

6 0
2 years ago
Read 2 more answers
A leaky faucet is losing water and is filling a 8-gallon bucket every 25 hours.At this rate,how many gallons of water will the f
Angelina_Jolie [31]

The rate of 8 gallons every 25 hours means that the faucet fills \frac{8}{25} gallons every hour.

Multiply the unit rate for the number of hours you're interested in to find

\dfrac{8}{25}\cdot 13 = \dfrac{104}{25}

6 0
3 years ago
For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10
professor190 [17]

The true statements are:

  • Tyson's expression is not equivalent to the original expression
  • The equivalent expression is:\frac{1}{2}g- \frac 1{5}

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}

Collect like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10}  -\frac{1}{10}

Evaluate the like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}

Tyler's equivalent expression is given as:

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}

Collect like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}

Evaluate the like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0
2 years ago
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