3 years ago

Find the measure of <1 A.) 30 B.) 45 C.) 15 D.) 60

Mathematics

1 answer:

nataly862011 [7]3 years ago

5 0

45 would most likely be right

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kupik [55]

the answer is to be 20

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3 years ago

Jake owns twice as many DVDs as Louis.Bo has sixty fewer DVDs than five times Louis’s collection. If Jake and Bo have the same a

almond37 [142]

There are 20 number of DVD's in Louis collection

Solution:

Let "J" be the number of DVD's with Jake

Let "B" be the number of DVD's with Bo

Let "L" be the number of DVD's with Louis

Given that Jake owns twice as many DVDs as Louis

So we can say,

number of DVD's with Jake = 2(number of DVD's with Loius)

J = 2L ------ eqn 1

Given that Bo has sixty fewer DVDs than five times Louis’s collection

So we can say,

number of DVD's with Bo = 5 times number of DVD's with Louis - 60

B = 5L - 60 ---- eqn 2

Given that Jake and Bo have the same amount of DVDs

number of DVD's with Jake = number of DVD's with Bo

J = B ---- eqn 3

Let us solve eqn 1, 2, 3 to find value of "L"

From eqn 1 and eqn 3,

2L = B ----- eqn 4

Substitute eqn 4 in eqn 2

2L = 5L - 60

2L - 5L = -60

-3L = -60

Thus there are 20 number of DVD's in Louis collection

4 0

3 years ago