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madreJ [45]
2 years ago
6

Find the measure of <1 A.) 30 B.) 45 C.) 15 D.) 60

Mathematics
1 answer:
nataly862011 [7]2 years ago
5 0
45 would most likely be right
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Jacques built a house that measured 75 feet long by 30 feet wide.
Sergio039 [100]
The area is 2250 square feet.
4 0
3 years ago
Antionette bought 2 2/3 pounds of grapes. if she bought bananas that weighed 1 1/4 times as much as the grapes, how much did the
vovikov84 [41]
Hey there!

To solve this problem, first turn the mixed numbers to improper fractions then multiply 2 2/3 and 1 1/4 . . .

2 2/3 = 8/3
1 1/4 = 5/4

8 x 5 = 40

3 x 4 = 12

= 40/12

Simplify 40/12 . . .

40/12 = 3 1/3 <--------

The answer to your question is option B.

The bananas weighed 3 1/3 pounds.

Hope this helps you.
Have a great day!

7 0
3 years ago
Solve 16x + 9 = 9y – 2x for y.<br> y =
liberstina [14]
Y= 2x + 1, hope this helps
4 0
3 years ago
Read 2 more answers
What is Permutations and Combinations?
marissa [1.9K]

Answer:

See below

Step-by-step explanation:

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

Permutation can be expressed in math as:

\displaystyle{_n P _r = \dfrac{n!}{(n-r)!} \ \ \ (n \geq r) }

where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.

Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:

Since there are 3 letters total and 3 selected letters to arrange then:

\displaystyle{_3 P _3 = \dfrac{3!}{(3-3)!}}\\\\\displaystyle{_3 P _3 = \dfrac{3 \times 2 \times 1}{0!}}\\\\\displaystyle{_3 P _3 = \dfrac{6}{1}}\\\\\displaystyle{_3 P _3 = 6}

Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:

ABC - 1

ACB - 2

BAC - 3

BCA - 4

CAB - 5

CBA - 6

Notice that if you do visually, you'll get the same answer as the calculation of permutation!

----

Combination can be expressed mathematically as:

\displaystyle{_n C _r = \dfrac{n!}{(n-r)!r!} = \dfrac{_n P _r}{r!} \ \ \ (n \geq r) }

The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.

Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:

Since there are 3 letters total and 3 selected letters:

\displaystyle{_3 C _3 = \dfrac{3!}{(3-3)!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{0!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{3!}}\\\\\displaystyle{_3 C _3 = 1}

Hence, there is only one way to select 3 letters. This makes sense because if you have 3 letters then you can only select 3 letters only one way.

5 0
2 years ago
-8(7 + x) = 137<br> What can be used to solve this problem
alexgriva [62]

Answer:

-24.5

Step-by-step explanation:

-56+-8x=137

-8x=196

x=-24.5

3 0
3 years ago
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