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padilas [110]
3 years ago
11

The zeros of a function are the values of x x for which the function is equal to zero. Enter a number in each blank to make true

statements about the function h(x)=(2x−2)(x−5) h(x)=(2x-2)(x-5) .
Mathematics
1 answer:
Anit [1.1K]3 years ago
8 0

Answer:

1 or 5

Step-by-step explanation:

Given the function h(x)=(2x−2)(x−5)

The zeros of h(x) are the values of x for which h(x)=0

h(x)=(2x−2)(x−5)=0

Note that if a.b=0, either a=0 or b=0.

Appying the above,

If (2x−2)(x−5)=0

Then:

2x−2=0 or x-5=0

2x=2 or x=5

x=1 0r 5

The zeroes of h(x) as defined are 1 or 5.

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19 you could’ve just used the calculator lol
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The input value 2.
Irina18 [472]
Your answer is 9.

Since you have

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Then you have -3(2) which is -6.

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When you add it up you get.

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What is the equation of the line represented by the table of values?
Shkiper50 [21]
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Write the equation of the circle whose center is (-4,8) and has a diameter of 18
svetoff [14.1K]

Answer:

(x + 4)^2 + (y - 8)^2 = 81

or

(x + 4)^2 + (y - 8)^2 = 9^2 depending on how your teacher wants it written.

Step-by-step explanation:

The standard form for a circle is

(x + h)^2 + (y + k)^2 = r^2

r is the radius.

You are given the diameter

r = d/2

r = 18/2

r = 9

So you already have the right hand side of the equation

(x + h)^2 + (y + k)^2 = 9*2

(x + h)^2 + (y + k)^2 = 81

You basically have h and k as well. They come from the center point.

h = 4

k = - 8

So the equation of the circle (and the answer) is

(x + 4)^2 + (y - 8)^2 = 81

One question remains. Why do the x and y values change signs? If you know what the distance formula is, then what you are finding is the distance r of all points on the circle from the center of the circle.

It is the distance formula that is actually the formula for the circle.

6 0
3 years ago
How do you substitute 4(x) into the inequality 1/2x+5y-10<0 to find the possible value of y?
Veseljchak [2.6K]
You put 4 in the X
1/2(4)+5y-10<0
2+5y-10<0
-8+5y<0
5Y<8
Y<8/5
3 0
3 years ago
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