Question

Find the magnitude of wx for w(6 -3 6) and x(6 3 4) A. 2sqrt10 B. 35 C. 4sqrt2 D. 32

Answer 1

Answer:

$|WX|=2\sqrt{10}$

Step-by-step explanation:

To find the distance between two points in there dimensional coordinate system, we use the formula;

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

The magnitude for  w(6 ,-3 , 6)  and x(6, 3, 4)

$|WX|=\sqrt{(6-6)^2+(3--3)^2+(4-6)^2}$

$|WX|=\sqrt{(0)^2+(6)^2+(-2)^2}$

$|WX|=\sqrt{0+36+4}$

$|WX|=\sqrt{40}$

$|WX|=2\sqrt{10}$

The correct choice is A.