Answer:
x=5
Step-by-step explanation:
Answer:
The test results support the claim
Step-by-step explanation:
The Coca-Cola Company reported that the mean per capita annual sales of its beverages in the United States was 423 eight ounce servings (Coca-Cola Company website, February 3, 2009).
Suppose you are curious whether the consumption of Coca-Cola beverages is higher in Atlanta, Georgia, the location of Coca-Cola’s corporate headquarters.
A sample of 36 individuals from the Atlanta area showed a sample mean annual consumption of 460.4 eight ounce servings with a standard deviation of s = 101.9 ounces. Using α = .05, do the sample results support the conclusion that mean annual consumption of Coca-Cola beverage products is higher in Atlanta?
Hx: u <= 423 oz
Ha: u > 423 oz (claim)
z(460.4) = (460.4-423)/[101.9/sqrt(36)] = 2.2022
p-value = P(z > 2.2022) = 0.0138
Conclusion: Since the p-value is less than 5%
reject Hx at the 5% significance level.
The test results support the claim.
The photo isnt popping up
Answer:
C
Step-by-step explanation:
Answer:
765 J
Step-by-step explanation:
We are given;
Mass of bucket = 30 kg
Mass of rope = 0.3 kg/m
height of building= 30 meter
Now,
work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand
Or W = W1 + W2
Work done in lifting the rope is given as,
W1 = Force x displacement
W1 = (30,0)∫(0.2x .dx)
Integrating, we have;
W1 = [0.2x²/2] at boundary of 30 and 0
W1 = 0.1(30²)
W1 = 90 J
work done in lifting the sand is given as;
W2 = (30,0)∫(F .dx)
F = mx + c
Where, c = 30 - 15 = 15
m = (30 - 15)/(30 - 0)
m = 15/30 = 0.5
So,
F = 0.5x + 15
Thus,
W2 = (30,0)∫(0.5x + 15 .dx)
Integrating, we have;
W2 = (0.5x²/2) + 15x at boundary of 30 and 0
So,
W2 = (0.5 × 30²)/2) + 15(30)
W2 = 225 + 450
W2 = 675 J
Therefore,
work done lifting the bucket (sand and rope) to the top of the building,
W = 90 + 675
W = 765 J
