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Shalnov [3]
3 years ago
8

Find the 68th term of the following arithmetic sequence. 16, 23, 30, 37,

Mathematics
2 answers:
Paul [167]3 years ago
6 0
7n+8

Then just go 7(68)+8

=484
taurus [48]3 years ago
6 0

Answer:

485

Step-by-step explanation:

first term = 16

second term = 23

common difference= second -. first

=23-16

=7

68 term= a + 67d

=16+67×7

=16 +469

=485

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