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3 years ago

Part C: Of the following choices, which equation is the best fit line for the data

Mathematics

1 answer:

KatRina [158]3 years ago

3 0

Step-by-step explanation:

Part C: Of the following choices, which equation is the best fit line for the data

As we can see from the data, the population size are decreased year by year, so the slope of the line of best fit must be a negative number.

So we have: C and D left.

Let x = 0, year 2005, the population size is 296 around 320, hence, we choose D.

D f(x) = -34x + 320

Part D: What is the predicted population size for the year 2010? How does that compare to the real data? Round to the nearest million.

year 2010, x =5 so let substitute x =5 into f(x) = -34x + 320

<=> f(x) = -34*5 + 320

= 150 mil

The result is smaller than the real data, (201-150 = 51 mil)

Part E: In what year is the population predicted to go extinct

the population predicted to go extinct when f(x)= 0

<=> -34x + 320 = 0

<=> x ≈ 9.4

So after 10 years, the the population predicted to go extinct

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n Juanita's Art History class Quizzes are worth 15% of the final grade, Exams are worth 55%, Projects are worth 25%, and Attenda

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Answer:

90.75%

Step-by-step explanation:

Given;

Of the total final score;

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Exam = 55%

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she had perfect attendance to class. 100% attendance;

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She got extra credit on her project with a score of 26 out of 25 possible points.

Project = 26/25 × 25% = 26%

80, 85, and 96 on the first three exams,each worth 100 points;

Total exam score = 80+85+96 = 261 out of 300

Of the total score;

Exam = 261/300 × 55% = 47.85%

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Quizzes = 119/150 × 15% = 11.9%

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= Quizzes+exam +project+attendance

= 11.9% + 47.85% + 26% + 5%

= 90.75%

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Answer:

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Show that the equation x^3+6x-5=0 has a solution between x=0 and x=1

Mnenie [13.5K]

Answer:

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

Step-by-step explanation:

The equation f(x) given is:

$f(x) = x^3+6x-5$

For x = 0. the value of the expression is:

$f(0) = 0^3+0-5\\f(0) = -5$

For x = 1, the value of the expression is:

$f(1) = 1^3+6-5\\f(1)=2$

Since the value of f(0) is negative and the value of f(1) is positive, then there is at least one value of x between 0 and 1 for which f(x) =0.

In other words, there is at least one solution for the equation between x=0 and x=1.

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