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2 years ago

What is the equation of the line that passes through the point (6, -6) and has a slope of (-2, -2)

Mathematics

1 answer:

shutvik [7]2 years ago

4 0

Answer:

y = -1/2x -3

Step-by-step explanation:

The steps to solve this include finding the slope of the line and finding the point where the line crosses the y axis.

Slope is Rise over Run or difference of the y values over the difference of the x values.

Rise = difference between -6 and -2 = 4

Run = difference between 6 and -2 = 8

So slope is 4/8. The line slants downward from left to right so the slope is also negative. Slope = - 4/8 or simplified to - 1 / 2

To find the y intercept, use the slope-intercept form equation:

y = mx + b where m is your slope and b is the y intercept. Solve for b and use one or both of your points that you were given along with your slope.

-6 = -1/2(6) + b OR -2 = -1/2(-2) + b

-6 = - 3 + b -2 = 1 + b

-3 = b -3 = b

Now you can use your calculated slope and calculated b to form your equation.

y = mx + b

y = - 1/2x -3

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2 years ago

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3 years ago

Read 2 more answers

Can someone please answer 8|x+2|-6=5|x+2|+3

Anettt [7]

Step-by-step explanation:

8|x+2|-6=5|x+2|+3

|8x+16|-6=|5x+10|+3

I've been thinking... Is that | or (? Are you sure it's |?

Oh well, I'm continuing...

8x+16-6=5x+10+3

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4 0

3 years ago

HELP I NEED HELP ASAP

victus00 [196]

Answer: (5, -2)

Step-by-step explanation:

$y= x-7\\2x+y=8$

Substitute x-7 for y in 2nd equation

$2x+ x-7 =8\\3x-7=8\\3x = 15\\x=5$

Solve for y

$y=5-7\\y=-2$

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2 years ago

Two equal groups of seedlings, and equal in height, were selected for an experiment. One group of seedlings was fed Fertilizer A

ser-zykov [4K]

Answer:

Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0

Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0

Here to test Fertilizer A height is greater than Fertilizer B

Two Sample T Test:

t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}

Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}

S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154

t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524

P value for Test Statistic of P(3.3524,26) = 0.0012

df = n1+n2-2 = 26

Critical value of P : t_{0.025,26}=2.05553

We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.

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2 years ago