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larisa [96]
3 years ago
9

Which ordered pair is a solution of the equation? y = 7 x − 3 y=7x−3

Mathematics
1 answer:
eimsori [14]3 years ago
8 0

Answer:

(1,4)

Step-by-step explanation:

Which ordered pair is a solution of the equation? y = 7 x − 3

a. (1,4) b. (-1,-4) c. both d. neither

Solution

y=7x-3

Solve by trying each ordered pair

a. (1,4)

x=1, y=4

Substituting the value of x and y into the equation

y=7x-3

4=7(1)-3

4=7-3

4=4

This is a true statement

b. (-1,-4)

x=-1, y=-4

Substitute the value into the equation

y=7x-3

-4=7(-1)-3

-4= -7-3

-4= -11

This is not a true statement

This true statement is when x=1 and y=4

So, the ordered pair (1, 4) is the solution

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The given question is a quadratic equation and we can use several methods to get the solutions to this question. The solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

<h3>Quadratic Equation</h3>

Quadratic equation are polynomials with a second degree as it's highest power.

An example of a quadratic equation is

y = ax^2 + bx + c

The given quadratic equation is 24x^2 + 2x = 15

Let's rearrange the equation

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The equation or formula of quadratic formula is given as

y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}

We can substitute the values into the equation and solve

y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}\\y = \frac{-2 +- \sqrt{2^2 -4 * 24 * (-15)} }{2*24} \\y = \frac{-2+-\sqrt{4+1440} }{48} \\y = \frac{-2+-\sqrt{1444} }{48} \\y = \frac{-2+- 38}{48} \\y = \frac{-2+38}{48} \\y = \frac{3}{4}\\ \\or\\y = \frac{-2-38}{48} \\y = \frac{-40}{48} \\y = -\frac{5}{6}

From the calculations above, the solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

Learn more on quadratic equation here;

brainly.com/question/8649555

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