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Alborosie
3 years ago
14

WILL GIVE BRAINLIEST ! 12 POINTS !

Mathematics
2 answers:
galben [10]3 years ago
4 0
1 over 2, 3 over 2 is the correct answer.
fenix001 [56]3 years ago
4 0
The answer would be (5/2),(7/2). Sorry it took a while to get to your answer!

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HELP!! Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 5 hours. Togeth
joja [24]

Answer:

  • first mechanic: $105/hour
  • second mechanic: $55/hour

Step-by-step explanation:

Let r represent the rate charged by the first mechanic. Then 160-r is the rate charged by the second mechanic. The total of charges is ...

  20r +5(160-r) = 2375

  15r +800 = 2375 . . . . . . eliminate parentheses

  15r = 1575 . . . . . . . . . . . . subtract 800

  r = 105 . . . . . . . . . . . . . . . divide by 15. First mechanic's rate.

  160-r = 55 . . . . . Second mechanic's rate

The first mechanic charged $105 per hour; the second, $55 per hour.

7 0
3 years ago
Read 2 more answers
Which of the following numbers is written in scientific notation?
nata0808 [166]

Answer:

i think is b

Step-by-step explanation:

8 0
2 years ago
Hi i just wanna know if i'm right on this math question<br><br> Thank you.
Stolb23 [73]

Answer:

Correct my guy or gal.

Step-by-step explanation:

6 0
3 years ago
What is the solution to the system of equations? x=4y 6 x-3y=4
ahrayia [7]
If you graph the two equations then you will find that they intersect at (-2,-2).

You then have to check your answer.

x=4y+6
(-2)=4(-2)+6
-2=-8+6
-2=-2

x-3y=4
(-2)-3(-2)=4
-2+6=4
4=4

8 0
3 years ago
Find the approximate area between the curve f(x) = -4x² + 32x and on the x-axis on the interval [0,8] using 4 rectangles. Use th
Doss [256]

Split up the interval [0, 8] into 4 equally spaced subintervals:

[0, 2], [2, 4], [4, 6], [6, 8]

Take the right endpoints, which form the arithmetic sequence

r_i=2+\dfrac{8-0}4(i-1)=2i

where 1 ≤ <em>i</em> ≤ 4.

Find the values of the function at these endpoints:

f(r_i)=-4{r_i}^2+32r_i=-16i^2+64i

The area is given approximately by the Riemann sum,

\displaystyle\int_0^8f(x)\,\mathrm dx\approx\sum_{i=1}^4f(r_i)\Delta x_i

where \Delta x_i=\frac{8-0}4=2; so the area is approximately

\displaystyle2\sum_{i=1}^4(-16i^2+64i)=-32\sum_{i=1}^4i^2+128\sum_{i=1}^4i=-32\cdot\frac{4\cdot5\cdot9}6+128\cdot\frac{4\cdot5}2=\boxed{320}

where we use the formulas,

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6

6 0
3 years ago
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