Answer:
(4) Both (1) & (2)
Explanation:
Viviparous germination is a type of seed germination in which seeds germinates but still attached with the plant body. This type of germination is present in plants such as Sonneratia and Rhizophora. In these plants, the embryo which is present inside the seed grows and break the seed coat and after that, it comes out the fruit which is still attached to the plant.
The respiratory system is a collection of organs involved in carrying out gas exchange in your body. Deep in the lungs, tiny sacs called alveoli take in oxygen from the atmosphere and release carbon dioxide.
Answer:
RADON GAS
Explanation:
Radon is a naturally occurring gas, which is produced due to the radioactive decay of the Radium element. It is one of the dense gas that is mostly concentrated in the lower portion of the houses, and are trapped in the cracks and fractures of the walls of houses and buildings.
Radon gas is an invisible, colorless and odorless gas, which is a very harmful gas, and exposure to Radon gas can cause an individual to suffer from cancer.
In recent studies, it has been found that in many parts of North America, a large number of residents are exposed to Radon gas, which led to an increased risk of cancer.
There is not that much information, so it is impossible to answer this question. I apologise.
Answer:
1/16
Explanation:
- scalloped (Xsd) is an X-linked recessive trait to Xsd+ (wild type)
- ebony (e) is an autosomal mutation recessive to e+ (wild type).
The two genes are independent because they are located on different chromosomes.
<h3>
<u>Parental generation:</u></h3>
True breeding scalloped female wild type for ebony (<em>Xsd Xsd e+e+</em>) mates with a true breeding male mutant only for ebony (<em>Xsd+ Y ee</em>).
The female only produces <em>Xsd e+</em> gametes. The male produces <em>Xsd+ e</em> or <em>Y e</em> gametes.<u> Therefore, the F1 females will have the genotype </u><u><em>Xsd Xsd+ e e+ </em></u><u>and the F1 males will have the genotype </u><u><em>Xsd Y e e+.</em></u>
If you complete a Punnett Square with the gametes the two F1 individuals can produce, you will get all the F2 proportions. The scalloped, ebony females have a<em> Xsd Xsd e e</em> genotype and appear in a 1/16 proportion.