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AfilCa [17]
3 years ago
7

A car requires 25 litres of petrol for covering a distance of 350 km how much petrol will be required by the car to cover a dist

ance of 1050 kilometre
pls it urgent​
Mathematics
2 answers:
solong [7]3 years ago
5 0
75 liters are required
jasenka [17]3 years ago
4 0
75 litres of petrol would be required
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Write and solve a real world problem that involves using the properties of congruent figures to find a missing measure
IrinaK [193]
A farmer has a pen that is 33 ft by 58 ft. what is the total amount of feet the farmer's pen will be. Answer) 7656ft.
7 0
3 years ago
GIVEN THAT TITAN HAS A RADIUS OF 2575 KM WHICH IS COVERED BY 600 KM ATMOSPHERE. WHAT
Ber [7]

Answer:

  87.4%

Step-by-step explanation:

The radius to the top of the atmosphere as a fraction of the moon's radius is ...

  (2575 +600)/2575 ≈ 1.23301

The ratio of the moon's volume with atmosphere to the moon's volume without is the cube of this, or 1.87456

Then the ratio of the atmosphere's volume to the moon's volume is ...

  (1.87456 -1)/1 = 0.87456

Atmospheric haze is about 87.4% of the moon's volume.

_____

We have assumed that the desired ratio is to the solid moon's volume, not the volume of moon and atmosphere together. The latter ratio would be 0.875 to 1.875 or about 46.7%.

3 0
4 years ago
Given g(x) = -x-2, find g(0)
Reika [66]

Answer:

g(0)=-2

Step-by-step explanation:

So we have the function:

g(x)=-x-2

And we want to find g(0).

To do so, substitute 0 into x:

g(0)=-(0)-2

Multiply:

g(0)=-2

So, the value of g(0) is -2.

And we're done!

3 0
3 years ago
Given the function f(x)=3x+5a / x^2-a^2 find the value of a for which f'(12) = 0
maria [59]
The function, as presented here, is ambiguous in terms of what's being deivded by what.  For the sake of example, I will assume that you meant

           3x+5a
<span> f(x)= ------------
</span>          x^2-a^2

You are saying that the derivative of this function is 0 when x=12.  Let's differentiate f(x) with respect to x and then let x = 12:

             (x^2-a^2)(3) -(3x+5a)(2x)
f '(x) = ------------------------------------- = 0 when x = 12
                [x^2-a^2]^2

(144-a^2)(3) - (36+5a)(24)
------------------------------------  =  0
               [   ]^2

Simplifying,

(144-a^2) - 8(36+5a) = 0

144 - a^2 - 288 - 40a = 0

This can be rewritten as a quadratic in standard form:

-a^2 - 40a - 144 = 0, or a^2 + 40a + 144 = 0.

Solve for a by completing the square:

a^2 + 40a + 20^2 - 20^2 + 144 = 0
        (a+20)^2    = 400 - 144 = 156

        Then a+20 = sqrt[6(26)] = sqrt[6(2)(13)] = 4(3)(13)= 2sqrt(39)

         Finally, a = -20 plus or minus 2sqrt(39)

You must check both answers by subst. into the original equation.  Only if the result(s) is(are) true is your solution (value of a) correct.
6 0
4 years ago
Question Help
hram777 [196]

Answer:

.3%, 21/7000=.003

Step-by-step explanation:

to make it by percent you multipy by 100

5 0
3 years ago
Read 2 more answers
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