3(5b-1)=5
Get rid of the brackets
15b-3=5
add 3 to both sides of the equation
15b=8
divide both sides of the equation by 15
b=0.53
4(3y-1)=20
12y-4=20
12y=24
y=0.5
Answer:
Step-by-step explanation:
The sum of two matrices is the sum of corresponding terms.
![\left[\begin{array}{ccc}3&1&0\\-1&2&4\\9&7&-2\end{array}\right] +\left[\begin{array}{ccc}5&2&4\\1&12&3\\11&3&-2\end{array}\right] =\left[\begin{array}{ccc}8&3&4\\0&14&7\\20&10&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%260%5C%5C-1%262%264%5C%5C9%267%26-2%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%262%264%5C%5C1%2612%263%5C%5C11%263%26-2%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D8%263%264%5C%5C0%2614%267%5C%5C20%2610%26-4%5Cend%7Barray%7D%5Cright%5D)
Answer:
66
Step-by-step explanation:
Plug in 5 for x
16 + 10(5)
16 + 50 = 66
Answer:
-31
Step-by-step explanation:
(2×x) - (2×5) = (3×x) + (3×7)
2x-10 = 3x+21
2x-3x = 21+10
-x = 31
therefore, x = -31
Answer:
B. The mean amount of
emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg
Step-by-step explanation:
A Type II error is the failure to reject a false null hypothesis.
Given the null and alternate hypothesis of a fuel company which wants to test a new type of gasoline designed to have lower
emissions.:

where
is the mean amount of
emitted by burning one gallon of this new gasoline.
If the null hypothesis is false, then:

A rejection of the alternate hypothesis above will be a Type II error.
Therefore:
The Type II error is: (B) The mean amount of
emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg.