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Maru [420]
3 years ago
8

Which inequalities are true? Check all that apply. Three-fifths < 0 Four-sixths greater-than one-half Nine-elevenths < 1 T

hree-eighths Eight-sixteenths greater-than one-half
Mathematics
1 answer:
Kipish [7]3 years ago
6 0

\frac{3}{5} < 0

\frac{8}{16} > \frac{1}{2}\\\\

<em><u>Solution:</u></em>

<em><u>We have to find the inequalities that are true</u></em>

<em><u>Option 1</u></em>

\frac{3}{5} < 0\\\\0.6 < 0

0.6 is not less than 0

Thus this inequality is not true

<em><u>Option 2</u></em>

\frac{4}{6} > \frac{1}{2}\\\\0.667 > 0.5

0.667 is greater than 0.5

Thus this inequality is true

<em><u>Option 3</u></em>

\frac{9}{11} < 1\\\\0.818 < 1

0.818 is less than 1

Thus this inequality is true

<em><u>Option 4</u></em>

\frac{8}{16} > \frac{1}{2}\\\\

0.5 = 0.5

Thus the above inequality is not true

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Determine whether the given description corresponds to an observational study or an experiment.
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Answer:Good luck hopefully somebody answer your question

Step-by-step explanation:

4 0
2 years ago
A standard deck of cards contains 52 cards. One card is selected from the deck.​(a)Compute the probability of randomly selecting
Aneli [31]

a. There are four 5s that can be drawn, and \binom43=4 ways of drawing any three of them. There are \binom{52}3=22,100 ways of drawing any three cards from the deck. So the probability of drawing three 5s is

\dfrac{\binom43}{\binom{52}3}=\dfrac4{22,100}=\dfrac1{5525}\approx0.00018

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of \frac8{52}=\frac2{13}\approx0.15 of getting drawn.

b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability \frac{12}{52}=\frac3{13}\approx0.23 of being drawn.

c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of \frac{16}{52}=\frac4{13}\approx0.31.

- - -

Note: \binom nk is the binomial coefficient,

\dbinom nk=\dfrac{n!}{k!(n-k)!}={}_nC_k=C(n,k)=n\text{ choose }k

6 0
3 years ago
Poppy, felix and Alexi sell 700 raffle tickets between them. Poppy sells twice as many tickets as Felix, and Alexi sells 25 more
slavikrds [6]
Let give Poppy = P, Felix = F, Alexi = A
so P+ F + A = 700 ----(1)
P = 2F ----(2)
A = 25 + P ---(3)
we will think in term of P

from (2) F = P/2

from (1) P + F + A = 700
P + P/2 + 25 + P = 700 ---(4)
(4) multiplied by 2
2P + P + 50 + 2P = 1400
5P + 50 = 1400
5P = 1350
so P = 270

so Poppy sold 270 tickets
Felix sold 135 tickets
and Alexi sold 295 tickets //
3 0
2 years ago
The ratio of Monarch butterflies to Queen butterflies at a butterfly farm was 5:2. If there are no additional butterflies at the
andrew-mc [135]
So we know if there are 5 groups/dozens of Monarch butterflies, there are 2 groups/dozens of Queen butterflies. In other words, there are 5 Monarch butterflies for every 2 Queen butterflies.

Then we can turn that into an equation.

5x = m \\ \\ 2x =q \\ \\ 5x + 2x = m + q
From the last equation we wrote we can see that the total number of butterflies in the farm is 7x.

When we compare the Queen butterflies to total butterflies, we get \frac{q}{m + q} = \frac{2x}{5x + 2x} = \frac{2x}{7x} = \frac{2}{7}

The ratio of Queen butterflies to total butterflies is 2:7.
7 0
2 years ago
What are the scale factor of ABC dilated to XYZ plz help
jekas [21]
<h3>Answer:  B) 2/3</h3>

====================================

Explanation:

The order is important for ABC and XYZ so we can see what letters pair up.

  • A pairs with X since they are the first letters
  • B pairs with Y since they are the second letters
  • C pairs with Z since they are the third letters

Based on that, we can see that AB pairs with XY as they are the first two letters of ABC and XYZ respectively.

Divide the length XY over AB and reduce

XY/AB = 10/15 = 2/3

We could also divide XZ over AC

XZ/AC = 14/21 = 2/3

and we get the same ratio

6 0
3 years ago
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