3 years ago

What’s is the surface area of this

1 answer:

6 0

2.8 multiplied by 2.8 to find the surface area of the base which is 7.84
4*1/2*2.8*5.5 to find the surface area of all four triangular faces which is 30.8
Plus them together 7.84 plus 30.8 which is 38.64

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Solve this using the quadratic formula. Show work<br><br> 2x^2+7x−5=0

kozerog [31]

Multiply the numbers (2*2=4)
$=\frac{-7+\sqrt{7^2-4\cdot \:2\left(-5\right)}}{2\cdot \:2}$

Apply the rule
$\sqrt{7^2+2\cdot \:4\cdot \:5}$

7^2 =49
$=\sqrt{49+2\cdot \:4\cdot \:5}$

Multiply
$\sqrt{49+40}$

Add
$\sqrt{89}$

$=\frac{-7-\sqrt{89}}{4}$

Final solution:
$x=\frac{-7+\sqrt{89}}{4},\:x=\frac{-7-\sqrt{89}}{4}$

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