All categories

3 years ago

2 3/ 7 can also be written as?

Mathematics

2 answers:

abruzzese [7]3 years ago

7 0

2 3/7 can also be written as 2.43

3/7 = 0.428 which rounded is 0.43 + 2 = 2.43

I hope this helps :)

Jet001 [13]3 years ago

6 0

The answer is 18/7, right?

You might be interested in

a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.

Vadim26 [7]

The first term is 612.

The common ratio is 1.08 and

The recursive rule is $a_{n} = a^{n-1} \times r$

Step-by-step explanation:

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

The first term :

In geometric sequence, the first term is given as $a_{1}$ .

⇒ $a_{1} = 612$

Now, the geometric sequence follows as 612, 661, ........

The common ratio (r) :

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

To find the recursive rule :

A geometric series is of the form a,ar,ar2,ar3,ar4,ar5........

Here, first term $a_{1} = a$ and other terms are obtained by multiplying by r.

Observe that each term is r times the previous term.
Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form $a_{n} = a^{n-1} \times r$

This is called recursive formula for geometric sequence.

We know that r = 1.08 and $a_{1}$ = 612.

To find the second term $a_{2}$ , use the recursive rule $a_{n} = a^{n-1} \times r$

⇒ $a_{2} = a^{2-1}\times r$

⇒ $a_{2} = a^{1}\times r$

⇒ $a_{2} = 612\times 1.08$

⇒ $a_{2} = 661$

3 0

3 years ago

Which statement corresponds to the values of x shown on the following number line? (Gray line is answer, dark black line is just

PSYCHO15rus [73]

Answer:

a)-4 5×<2

Step-by-step explanation:

<h3>#CarryOnLearning</h3>

6 0

2 years ago

Graph y = 3(x + 2)3 - 3 and describe the end behavior.

-BARSIC- [3]

1) The function is 3(x + 2)³ - 3

2) The end behaviour is the limits when x approaches +/- infinity.

3) Since the polynomial is of odd degree you can predict that the ends head off in opposite direction. The limits confirm that.

4) The limit when x approaches negative infinity is negative infinity, then the left end of the function heads off downward (toward - ∞).

5) The limit when x approaches positive infinity is positivie infinity, then the right end of the function heads off upward (toward + ∞).

6) To graph the function it is important to determine:
- x-intercepts
- y-intercepts
- critical points: local maxima, local minima, and inflection points.

7) x-intercepts ⇒ y = 0

⇒ 3(x + 2)³ - 3 = 0 ⇒ (x + 2)³ - 1 = 0


⇒ (x + 2)³ = -1 ⇒ x + 2 = 1 ⇒ x = - 1


8) y-intercepts ⇒ x = 0

y = 3(x + 2)³ - 3 = 3(0 + 2)³ - 3 = 0 - 3×8 - 3 = 24 - 3 = 21


9) Critical points ⇒ first derivative = 0


i) dy / dx = 9(x + 2)² = 0


⇒ x + 2 = 0 ⇒ x = - 2


ii) second derivative: to determine where x = - 2 is a local maximum, a local minimum, or an inflection point.


y'' = 18 (x + 2); x = - 2 ⇒ y'' = 0 ⇒ inflection point.


Then the function does not have local minimum nor maximum, but an inflection point at x = -2.


Using all that information you can graph the function, and I attache the figure with the graph.

3 0

3 years ago

[ Cuiu be made.

shutvik [7]

Answer:

24/36 = 12 x 2/12 x 3 = 2/3.

Step-by-step explanation:

4 0

3 years ago

Let S denote the plane region bounded by the following curves:

oee [108]

The volume of the solid of revolution is approximately 37439.394 cubic units.

<h3>How to find the solid of revolution enclosed by two functions</h3>

Let be $f(x) = e^{\frac{x}{6} }$ and $g(x) = e^{\frac{35}{6} }$ , whose points of intersection are $(x_{1},y_{1}) =(0,1)$ , $(x_{2}, y_{2}) = (35, e^{35/6})$ , respectively. The formula for the solid of revolution generated about the y-axis is: