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Zinaida [17]
4 years ago
7

1)Pong paid $20.40 in interest on her credit card last month. The monthly interest rate for her credit card is 1.7% of the balan

ce she owes. What was Pong’s balance last month? 3 marks
Mathematics
1 answer:
mote1985 [20]4 years ago
4 0
We name her balance B so we have

B x1.7%=20.40
B x 1.7/100=20.40
B x 1.7=20.40 x 100
B x 1.7=2040
B=2040/1.7
B=1200

Maybe we could substract the amount that she paid for the interest so her balance may be 1200-20.40=1179.60 instead of 1200
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3+(2+8)2ndpower ÷4×(1/2) 4th power​
PIT_PIT [208]

Answer:

412

Step-by-step explanation:

You have to follow PEMDAS and solve the problem carefully.

\frac{3+(2+8)^{2} }{4*(\frac{1}{2} )^{2} }  =\frac{3+(10)^{2} }{4*(\frac{1}{2} )^{2} } = \frac{3+100}{4*(\frac{1}{2} )^{2} } = \frac{103 }{4*(\frac{1}{2} )^{2} }

\frac{103 }{4*(\frac{1}{2} )^{2} } = \frac{103 }{4*(\frac{1}{16})} } = \frac{103 }{\frac{1}{4} } =\\103*4\\=412

8 0
3 years ago
Hi please i nedd help with these questions .
Vlad1618 [11]

Answer:

Step-by-step explanation:

#1:

\frac{18m^2u}{16n^3v^2} \div \frac{24m}{15nu^3}*\frac{8n^2v^3}{30m^3u}

division sign means that we flip the fraction

\frac{18m^2u}{16n^3v^2} * \frac{15nu^3}{24m}*\frac{8n^2v^3}{30m^3u}

now we can multiply all the constants together and all variables

m: (m^2)/(m*m^4) = (m^2)/(m^4) = 1/(m^2)\\u: (u * u^3)/(u) = (u^4)/(u) = u^3\\n: (n*n^2)/(n^3) = 1\\v: (v^3) / (v^2) = v\\(18*15*8)/(16*24*30) = \frac{3}{16}

now we can combine all the parts

\frac{3u^3v}{16m^2}

#2:

\frac{24a^2b^3c}{9bc^3}\div\frac{4a^5bc^3}{27a^3b^2c}

\frac{24a^2b^3c}{9bc^3}*\frac{27a^3b^2c}{4a^5bc^3}

a: (a^2 * a^3)/(a^5) = 1\\b: (b^3 *b^2)/(b*b) = b^3\\c: (c*c)/(c^3*c^3)= 1/(c^4)\\(24*27)/(9*4)= 18

\frac{18b^3}{c^4}

3 0
3 years ago
Read 2 more answers
Monica is attempting to factor the expression 18x2 + 27x – 5. In her first step, she rewrites the expression as 18x2 + 32x – 5x
lisabon 2012 [21]

Answer:

B


Step-by-step explanation:

For quadratic expression in this form, the first step is to multiply the number in front of x^2 with the last term, the constant (with the sign in front as well). This is the "multiplied number".

Step 2 is to come up with 2 numbers which when multiplied is equal to the "multiplied number" in step 1 above and also add to the number in front of x.


For this problem, we would need 2 numbers that

  • Add up to 27, and
  • When multiplied, comes to -90 <em>(18 * -5 = -90)</em>

They already found the 2 numbers as expressed in the form shown  18x^2+32x-5x-5. The 2 numbers are +32 and -5.


<em><u>Do they add up to 27, as required?</u></em>

Yes, 32-5=27

<u><em>Do they come to -90 when multiplied?</em></u>

No, 32 * -5 = -160


Hence, they add up, BUT NOT multiplied.

So the answer choice B is right.

5 0
3 years ago
Plz hurry and help it’s not a texts it’s a study guide.
Veronika [31]

Answer:

I do not know the answer but I think it is (1,0) x (-3,4)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which equation has a graph that is a parabola with a vertex at (5, 3)?
frozen [14]

Answer: The equation that has a graph which is a parabola with a vertex at (5, 3) would be y = (x – 5)^2 + 3. The general form of a parabola which the vertex is not in the origin is expressed as y = a(x - h)^2 + k where (h,k) represents the vertex.

8 0
3 years ago
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