Answer:
No real roots
Step-by-step explanation:
Given
7x² + 5x + 1 = 0 ← in standard form
with a = 7, b = 5, c = 1
To determine the nature of the roots use the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then roots are real and distinct
• If b² - 4ac = 0 then roots are real and equal
• If b² - 4ac < 0 then the roots are not real
Here
b² - 4ac = 5² - (4 × 7 × 1) = 25 - 28 = - 3
Thus the 2 roots are not real
21+4(32-5)=448
I think it’s 448
Answer:
B.
Step-by-step explanation:
I have attached the work to your problem.
Please see the attachment below.
I hope this helps!
Answer:
<h2>length= 40cm</h2><h2>width= 120cm</h2><h2>
Step-by-step explanation:</h2>
Area of a rectangle= lenght× width
Dimensions of 1st rectangle: L,W
Dimensions of 2nd rectangle: L+10; W+4
Hence,
LW = 480__________(1)
(L-10)(W+4) = 480_______(2)
LW = LW+4L - 10W - 40
4L = 10W +40
2L = 5W + 20
L = (5/2)W + 10_________(3)
But LW = 480 (from equation one)
So, W = 480/L
substitute as= 480/L into equation (3)
L = (5/2)(480/L)+10
L = 1200/L + 10
L^2 - 10L - 1200 = 0
factorising.
we're have,
(L-40)(L+30) = 0
therefore, since L can't be negative , L = 40
L = 40 cm (length)
Then 480/L = W = 120 cm (width)
<h2>therefore L= 40cm and W= 120cm</h2>
25 remainder 6 is how many times
