Answer:
{290,315,340, 365, 390, 415, 440, 465} That's the answer. Its hard for me to explain how i got it.
The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16
/2!+...........
Given a function f(x)=9/x,a=-4.
We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.
The taylor series of a function f(x)=
Where the terms in f prime
(a) represent the derivatives of x valued at a.
For the given function.f(x)=8/x and a=-4.
So,f(a)=f(-4)=8/(-4)=-2.
(a)=
(-4)=-8/(
=-8/16
=-1/2
The series of f(x) is as under:
f(x)=f(-4)+

=-2+2(x+4)/1!-24/16
/2!+...........
Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16
/2!+...........
Learn more about taylor series at brainly.com/question/23334489
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Answer:
4
Step-by-step explanation:
The x coordinate is the same so the distnce is only the difference in y
5 - 1 = 4
Yes, because it is continuous on [0,2] and differentiable on (0,2), the theorem states that there must exist some value c where a line tangent to c is parallel to the secant line through 0 and 2.
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