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nordsb [41]
3 years ago
14

Calculate the length.

Mathematics
2 answers:
deff fn [24]3 years ago
8 0
A squared+B squared=C squared
6 squared+B squared=7 squared
36+B squared=49
B squared=49-36=13
B squared=13
b=square root of 13
b=3.61
choice B
Nataly_w [17]3 years ago
5 0
A^2 + B^2 = C^2

6^2 + B^2 = 7^2

36 + B^2 = 49

B^2 = 13

B = 3.61

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Who can help me please
lakkis [162]
The dimensions of the bottom of the drawer are:
20 cm × 40 cm

So the area is : 800 cm² (rectangular shaped)

The area formula of a circle is:
\pir²
The diameter of the plate is 20cm
so the radius is half the diameter which is 10cm
Apply the given to the formula:
\pi(10)²
100\pi
314.16 cm²

2 plates in the bottom drawer
Area of two plates:
2 × 314.16
628.32 cm²

Area of the non-covered space in the bottom drawer:
Area of drawer - area of two plates
800 - 628.32
171.68 cm²
7 0
3 years ago
At an archeological​ site, the remains of two ancient step pyramids are congruent. If ABCD is congruent to EFGH, find GH
Alona [7]

Answer:

40 ft

Step-by-step explanation:

If two polygons are congruent to one another, therefore, it implies that the angles and sides of one is congruent to the corresponding sides and angles of the other.

Given that ABCD is congruent to EFGH, therefore:

CD ≅ GH

Since CD = 40 ft, therefore, GH will be 40 ft.

8 0
3 years ago
Which expression forms an equation with the given expression? 24 – 5 • 2 = ___________ A. (5 + 3) • 2 B. 2(6 + 1) C. 5 • 8 – 2 D
zhenek [66]
D. the rest is because of the characters rule
5 0
3 years ago
Read 2 more answers
Ana has been adding $30 to her saving account every month. Which model could represent the money in Ana’s saving account (y) aft
Gekata [30.6K]

Answer:

y = 30x

Step-by-step explanation:

y is the amount of money

30 is the constant, the amount of money she gets per x, month

5 0
3 years ago
A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the
Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= \pi r^2h

According to the problem,

\pi r^2 h=25

\Rightarrow h=\frac{25}{\pi r^2}

The surface area of the base of the can is = \pi r^2

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× \pi r^2)

The lateral surface area of the can is = 2\pi rh

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× 2\pi rh)

                                                 =\$2.5 \pi r h

Total cost of metal is C= 2.00 \pi r^2+2.5 \pi r h

Putting h=\frac{25}{\pi r^2}

\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}

\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}

Differentiating with respect to r

C'=4\pi r- \frac{62.5}{ r^2}

Again differentiating with respect to r

C''=4\pi + \frac{125}{ r^3}

To find the minimize cost, we set C'=0

4\pi r- \frac{62.5}{ r^2}=0

\Rightarrow 4\pi r=\frac{62.5}{ r^2}

\Rightarrow  r^3=\frac{62.5}{ 4\pi}

⇒r=1.71

Now,

\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0

When r=1.71 cm, the metal cost will be minimum.

Therefore,

h=\frac{25}{\pi\times 1.71^2}

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0
3 years ago
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