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![\beta x^{2} }1&2&3\\4&5&6\\7&8&9\end{array}\right] x_{123} \lim_{n \to \infty} a_n \sqrt{x} \sqrt[n]{x} x_{123} \neq \pi](https://tex.z-dn.net/?f=%20%5Cbeta%20%20x%5E%7B2%7D%20%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20x_%7B123%7D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%20%5Csqrt%7Bx%7D%20%20%5Csqrt%5Bn%5D%7Bx%7D%20%20x_%7B123%7D%20%20%5Cneq%20%20%5Cpi%20)
Calculate the length.
2 answers:
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Let the width be x, then the length is x + 12.
Area = length x width = x(x + 12) = 589
Solving the quadratic equation, we have that
x = 19 feet
i.e. the width is 19 feet.
Area = length x width = x(x + 12) = 589
Solving the quadratic equation, we have that
x = 19 feet
i.e. the width is 19 feet.
So, after one year will will have the new population of 23 000 * (100 %+2%)
(the 100 % is the old population and the 2% is the increase), that is:
23000*1.02=23460
(102 % can be represented as 1.02)
And for the next years, we have to repeat the procedure.
a more generic rule would be:
y=23000*
(x is the number of years passed)
(the 100 % is the old population and the 2% is the increase), that is:
23000*1.02=23460
(102 % can be represented as 1.02)
And for the next years, we have to repeat the procedure.
a more generic rule would be:
y=23000*