If , n^-3 = 1/8 then n would be which of the following? -1/2 -2 2 1/2

Mathematics

2 answers:

lions [1.4K]2 years ago

4 0

Answer:

Step-by-step explanation:

${n}^{ - 3} = \frac{1}{8} \\ \\ {n}^{ - 3} = \frac{1}{ {2}^{3} } \\ \\ {n}^{ - 3} = {2}^{ - 3}.. (\because \frac{1}{a^n} = a^{-n}) \\ \\ n = 2 \\(\because exponents \: are \: same\: hence\: \\bases\: will \: also\: be\: equal)$

Lady_Fox [76]2 years ago

3 0

Answer:

n = 2

Step-by-step explanation:

$n^{-3} = \frac{1}{8}\\\\ = \frac{1}{2^{3}}\\\\ = 2^{-3}\\$

Therefore, n= 2

A number or variable with negative exponent is represented by positive exponent by taking its reciprocal and vice versa

$a^{-n} = \frac{1}{a^{n}}$

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