Answer:
3x-x+2=4
Step-by-step explanation:
The domain of f(x)=2^x would be the x values. This would include all values that you can input as x in order to make this problem work. The domain of a function is usually all real numbers. The range of f(x)=2^x would be the y values. This would include all values that would be the output for the y value. An example of this would be if you used 2 as x then the function would read f(x)=2^2. The y would equal 4 which would be included in the range of this function. To find the domain and range of the inverse you would follow the proper steps to get the inverse of the function which would be x=2^y. The domain would be the x values and the range would be the y values. If you put 4 as x which would be your input for the domain you would get 2^4 = 16 for the y which would be the range.
H + 2 divided by 4
Please mark as brainliest!
Answer:
3x^2 -4
Step-by-step explanation:
F(x)=2x^2+3 and g(x)=x^2-7
(f+g)(x) =
We add the two functions together
(f+g)(x) =2x^2+3+x^2-7
I like to line them up vertically
(f+g)(x) =
2x^2 +3
+x^2 -7
------------------
3x^2 -4
<span>150+10c+150-10c=1.5(15-c)(15+c)300=1.5(225-c^2)300=337.5-1.5c^2200=225-c^2c^2=25c=5speed of current=5 mph<span>
</span></span>
All we need is to put this form in the vertex form f(x) = (ax+b)^2 + c
So we have <span>f (x)= 3x^2+12x+11 ....
Let's complete the square (if you aware of it)
</span><span>
f(x)= 3x^2+12x+11 = 3(x^2+4x)+11 = 3(x^2+4x+4-4)+11
=</span><span> 3([x^2+4x+4]-4)+11 = 3[(x+2)^2-4]+11 =3</span><span>(x+2)^2 - 12 +11 = 3</span><span><span>(x+2)^2 -1
so our form would be:

Here is a parabola with vertex of (-2,-1) and with positive </span> slope (concave up)
</span>
I hope that
helps!