Answer:
a
Step-by-step explanation:
![\sqrt[4]{144a^{12}b^{3}} = \sqrt[4]{4^{2}*3^{2}a^{12}b^{3}}=\\= \sqrt[4]{2^{4}*3^{2}a^{12}b^{3}}=2a^{3}\sqrt[4]{3^{2}b^{3}} =\\}=2a^{3}\sqrt[4]{9b^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B144a%5E%7B12%7Db%5E%7B3%7D%7D%20%3D%20%5Csqrt%5B4%5D%7B4%5E%7B2%7D%2A3%5E%7B2%7Da%5E%7B12%7Db%5E%7B3%7D%7D%3D%5C%5C%3D%20%5Csqrt%5B4%5D%7B2%5E%7B4%7D%2A3%5E%7B2%7Da%5E%7B12%7Db%5E%7B3%7D%7D%3D2a%5E%7B3%7D%5Csqrt%5B4%5D%7B3%5E%7B2%7Db%5E%7B3%7D%7D%20%3D%5C%5C%7D%3D2a%5E%7B3%7D%5Csqrt%5B4%5D%7B9b%5E%7B3%7D%7D)
Answer:
2.83
Step-by-step explanation:
using the pythagorean theorem, 
≈
Answer:
50
Step-by-step explanation:
add 5 to -25 to get -2/5x by itself.
In this problem, it is important to take note that the number of numbers to be utilized isn't specified so it can be up to a thousand numbers. It wasn't also specified if repeating of numbers is allowed or not. So with those taken into consideration and the condition presented in mind, the numbers that can give you 8 when added and 30 when multiplied are 2, 3, 5, -1, and another -1. The derivation from this is mainly from factorization and a little bit of logic.
here is the solution.
2 x 3 x 5 x -1 x -1 = 30
6 x 5 x -1 x -1 = 30
30 x -1 x -1 = 30
-30 x -1 = 30
30 = 30
2 + 3 + 5 + -1 + -1 = 8
5 + 5 + -1 + -1 = 8
10 + -1 + -1 = 8
9 + -1 = 8
8 = 8
