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erastovalidia [21]
4 years ago
9

Are the polygons similar? If they are, choose the correct similarity statement and scale factor. Not drawn to scale.

Mathematics
1 answer:
Dvinal [7]4 years ago
8 0

Option B: $\Delta R S T \sim \Delta UV W ; \frac{5}{6}$

Explanation:

The polygons are similar because in $\Delta R S T$, the measure of ∠R=32°

Also, in $\Delta U V W$, the measure of ∠U=32°

Now, we shall find the scale factor,

Since, $\Delta R S T \sim \Delta U V W$, then the sides are proportional which is given by,

\frac{RS}{UV}

Substituting the values of RS and UV from the figure, we get,

\frac{10}{12}

Simplifying, we have,

$\frac{5}{6}$

Thus, the scale factor is $\frac{5}{6}$

Hence, Option B is the correct answer.

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Fittoniya [83]

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3 years ago
Which equation can be used to determine the number of passenger stops, p, Mr. Martin had on Tuesday? 14 = 0.5p + 12 14 = 12p + 0
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14=0.5p+12

Step-by-step explanation:

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6 0
3 years ago
Geometry Help! 30 POINTS! + BRAINLIEST
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4 years ago
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Justin is skeet shooting. The height of the skeet is modeled by the equation h= -5t^2 +32t + 2, where h represents the height in
Rama09 [41]

Answer:

0.05 seconds; 2.575 m off the ground

Step-by-step explanation:

This is a system of equations that you need to solve for the variables t and h.

h = -5t² + 32t + 2

h = 31.5t + 1

Since h will be the same when the bullet and skeet collide, then h is the same in both equations and can be set equal to each other and then you can solve for t.

-5t² + 32t + 2 = 31.5t + 1

-5t² + 32t + 2 - 31.5t - 1= 31.5t + 1 - 31.5t -1 (move everything to the left side)

-5t² + 0.5t + 1 = 0 (combine like terms)

Now we can use the quadratic formula to solve for the time.

t = \frac{-.5 +/- \sqrt{.25 - 4(-5)(1)}  }{2(-5)} (substitute)

t = \frac{-.5 +/- \sqrt{.25 + 20}  }{-10} (multiply)

t = \frac{-.5 +/- \sqrt{20.25}  }{-10} (add)

t = \frac{-5 +/- 4.5}{-10} (square root)

t = -0.5/-10 or -9.5/-10 (combine like terms in each situation)

t = 0.05 or .95 (divide)

Since it will only hit it once, the first time it hits is the amount of time, therefore it takes .05 seconds to hit the skeet.

Next, substitute t into one of the equations to find the height at which it occurs.

h = 31.5(0.05) + 1 (substitute)

h = 1.575 + 1 (multiply)

h = 2.575 (add)

Therefore the skeet will be 2.575 meters off the ground.

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3 years ago
Brandon is thinking of a number that is divisible by 6 and 8 . What is the smallest number that Brandon could think of
a_sh-v [17]

since

6 = 2 * 3 <--- two factors


8 = 2 * 2 * 2 <--- three factors


and since the "2" is there on each, then we can just use that instance of it once.


so instead of using 2 * 3 * 2 * 2 * 2, we'll use 2 * 3 * 2 * 2, and that is our LCD.


2 * 3 * 2 * 2 = 24.

4 0
4 years ago
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