The ladder and the wall it leans on are illustrations of right triangle
The horizontal distance from the base of the ladder is 5.41 feet
<h3>How to determine the horizontal distance?</h3>
The given parameters are:
Length (L) = 26 feet
Angle of elevation (θ) = 78 degrees
The horizontal distance (D) is calculated using the following cosine ratio
cos(θ) = D/L
Substitute known values
cos(78) = D/26
Make D the subject
D = 26 * cos(78)
Multiply
D = 5.41
Hence, the horizontal distance from the base of the ladder is 5.41 feet
Read more about right triangles at:
brainly.com/question/2437195
<h3>
Answer:</h3>
<h3>
Step-by-step explanation:</h3>
We can let the variables A and B stand for the length in inches of fish A and fish B, respectively.
If we assume each person bought fish having a total length of 1 inch per gallon of aquarium, then we can write equations ...
... 3A +2B = 33 . . . . . total length of Marta's fish
... 3A +4B = 45 . . . . . total length of Hank's fish
Subtracting the first equation from the second, we get ...
... 2B = 12
... B = 6 . . . . . divide by 2
Using this value in the first equation, we have ...
... 3A + 2·6 = 33
... 3A = 21 . . . . . . . . subtract 12
... A = 7 . . . . . . . . . . divide by 3
Fish A is 7 inches long; fish B is 6 inches long.
You just want to simplify right?!
45. (a^2b^3)(ab)^-2
= (a^2b^3)(a^-2b^-2)
= b
46. (-3x^3y)^2(4xy^2)
= (-9x^6y^2)(4xy^2)
= -36x^7y^4
47. 3c^2d(2c^3d^5) / 15c^4d^2
= 6c^5d^6 / 15c^4d^2
= 2/5c1/4x^4
48. -10g^6h^9(g^2h^3) / 30g^3h^3
= -10g^8h^12 / 30g^3h^3
= -1/3g^5h^9
49. 5x^4y^2(2x^5y^6) / 20x^3y^5
= 10x^9y^8 / 20x^3y^5
= 1/2x^6 1/3y^3
50. -12n^7p^5(n^2p^4) / 36n^6p^7
= -12n^9p^9 / 36n^6p^7
= -1/3n^3p^2
(Sorry it’s messy it’d look better if my phone could actually put the numbers to the power)
I would divide the 18000 by 13.26 to get the number of hours needed.
18000/13.26~169.7 days with 8 hour shifts.
Answer:
14
Step-by-step explanation:
When you plug this expression into the calc, you should get 14 as your answer.
