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allsm [11]
3 years ago
15

Greatest common factor M^3n and 5m^5n^2

Mathematics
1 answer:
xenn [34]3 years ago
8 0

Answer:

m³n

Step-by-step explanation:

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Is Y=MX^2+B a function?
Tju [1.3M]

Answer:

I don't think so but I am not for sure

Step-by-step explanation:

3 0
2 years ago
if a 14 foot tree casts a 8 foot long shadow. how tall is a tree that casts a 4 foot long shadow?
kvasek [131]

7-foot

EXPLANAT

Given:

14 foot tree

8foot shadow

4foot shadow

Let h be the height of a tee that casts a 4 foot long shadow.

Using proportion;

14 foot = 8 ft shadow

h = 4 ft shadow

Cross - multiply

8h = 56

Divide both-side by 8

h = 7 foot.

Hence, the tree is 7-foot.

4 0
1 year ago
HELP Luna observed that in the last 12 issues of Rise Over Run Weekly, 384 of the 960 pages contained an advertisement.
Veseljchak [2.6K]
Well, 12 issues end up as 960 pages total

so... if in 960 pages, 384 are ads, what about 80 pages?

well \bf \begin{array}{ccllll}
pages&ads\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
960&384\\
80&x
\end{array}\implies \cfrac{960}{80}=\cfrac{384}{x}

solve for "x"
7 0
3 years ago
Read 2 more answers
a twelve sided die with side labeled 1-12 will be rolled once. What is the probability of rolling a number less than 9?
puteri [66]
12 possible outcomes
any number less than 9 is 8 and below
8 sides of the dice are less than 9 out of 12 total sides
8/12 is the chance you’ll roll lower than 9

2/3 or 66% chance you’ll roll a number lower than 9
7 0
1 year ago
Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet:
Phoenix [80]

6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

<u>Step-by-step explanation:</u>

We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find  how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:

Trenton's pet: 4/5 cup of dry food•

With 4/5 per day , for 14 days :

⇒ 14(\frac{4}{5} )

⇒ 14(0.8 )

⇒ 11.2

Maria's pet: 1.25 cups of dry food.

With 1.25 per day , for 14 days :

⇒ 14(1.25 )

⇒ 17.5

Subtracting Maria's - Trenton's :

⇒ 17.5-11.2=6.3

That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

3 0
3 years ago
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