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AlexFokin [52]
3 years ago
8

Can anyone help me please and explain this: Write "60 pounds for $6.60" as a unit rate per ounce to the nearest tenth. 1 pound=

16 ounces A: 1 lb/176 cents B: 3 lb/ 33 cents C: 1 lb/ 3.8 cents D: 1 lb/ 0.7 cents
Mathematics
1 answer:
Pepsi [2]3 years ago
6 0
<span>1 pound = 16 ounces
so 60 pounds = 60 x 16 = 960 ounces.
$6.60/960 =0.006875 per ounce.
0.006875 x 16 ounces = 0.11 (11 cents per pound)

<span>3 pounds x 0.11= 33 cents 

answer is B</span></span>
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A ping pong ball has a 75% rebound ratio. When you drop it from a height of k feet, it bounces and bounces endlessly. If the hei
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The movement of the ping pong ball follows a exponential progression.

  • The expression for the k-th bounce is: \mathbf{T_k = 235 \times (0.75)^k}
  • The height after the 6th bounce is 41.82 ft
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<u>1. Ping pong ball</u>

The given parameters are:

\mathbf{a = 235} --- the initial height

\mathbf{r = 75\%} --- the common ratio

<u>(a) The expression after bouncing k times</u>

To do this, we make use of

\mathbf{T_n = a \times r^n}

So, we have:

\mathbf{T_n = 235 \times (0.75)^n}

In this case; k = n.

So, the equation becomes

\mathbf{T_k = 235 \times (0.75)^k}

Hence, the expression for the k-th bounce is: \mathbf{T_k = 235 \times (0.75)^k}

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<u>(b) The height after bouncing 6 times</u>

This means that k = 6.

So, we have:

\mathbf{T_k = 235 \times (0.75)^k}

\mathbf{T_6 = 235 \times (0.75)^6}

\mathbf{T_6 = 41.82}

Hence, the height after the 6th bounce is 41.82 ft

<u>(c) The total distance after the 12th bounce</u>

First, we calculate the total height after the 12th bounce using:

\mathbf{S_k = \frac{a(1 - r^k)}{1 - r}}

So, we have:

\mathbf{S_k = \frac{235 \times (1 - 0.75^{12})}{1 - 0.75}}

\mathbf{S_k = \frac{235 \times (0.968)}{0.25}}

\mathbf{S_k = 909.92}

So, the total distance is:

\mathbf{Distance = 2 \times S_k - a}

\mathbf{Distance = 2 \times 909.92 - 235}

\mathbf{Distance = 1584.84}

Hence, the total distance after the 12th bounce is 1584.84ft.

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The given parameters are:

<em />\mathbf{r = 2/2hr}<em> --- rate</em>

<em />\mathbf{a = 120}<em> --- initial number of cells</em>

<em />\mathbf{t = 18}<em> --- number of 2 hours is a day and a half</em>

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So, the number of bacteria is:

\mathbf{T_t = ar^t}

This gives

\mathbf{T_t = 120 \times 2^{18}}

\mathbf{T_t = 31457280}

Hence, there will be 31457280 bacteria after a day and a half.

Read more about exponential functions at:

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