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Fiesta28 [93]
3 years ago
10

AB = 44 + 3xBC = 33 + yCD = 64 − xAD = 48 − 2yQuadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruen

t. Prove that quadrilateral ABCD is a parallelogram by finding the lengths (in centimeters) of the opposite side pairs?A)51 cm , 30 cmB)55 cm , 33 cmC)59 cm , 38 cmD)64 cm , 42 cm
Mathematics
1 answer:
Otrada [13]3 years ago
3 0

The lengths (in centimeters) of the opposite side pairs are 59 cm , 38 cm. Option C) is the correct answer.

<u>Step-by-step explanation</u>:

<u>step 1</u> :

Given that,

Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent.

<u>step 2</u> :

The opposite sides are AB and CD respectively.

The another opposite sides are BC and AD respectively.

<u>step 3</u> :

If both pairs of opposite sides are congruent, then

AB = CD

44+3x = 64-x

3x+x = 64-44

4x = 20

x = 5

<u>step 4</u> :

BC = AD

33+y = 48-2y

y+2y = 48-33

3y = 15

y = 5

<u>step 5</u> :

Subsitute x=5 and y=5 in any of the given sides,

CD = 64-x = 64-5 = 59

∴ CD = 59 cm

BC = 33+y = 33+5 = 38

∴ BC = 38 cm

The lengths of the opposite side pairs are 59 cm , 38 cm.

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In rectangle PQRS, PR = 11x – 20and QS = x + 160.
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Answer:

\large \boxed{1.\, x = 18; 2.\, 178}

Step-by-step explanation:

1. Value of x

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\begin{array}{rcll}11x - 20 & = & x + 160 & \\11x &= & x + 180 & \text{Added 20 to each side}\\10x & = & 180 & \text{Subtracted x from each side}\\x& = & \mathbf{18} &\text{Divided each side by 10}\\\end{array}\\\large \boxed{\mathbf{x = 18}}

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