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VMariaS [17]
3 years ago
12

Each day, a local dog shelter spends an average of $2.40 on food per dog. The manager estimates the shelter's daily expenses, as

suming there is at least one dog in the shelter, using the function E(x)= 30+2.40x . Which statements regarding the function are correct?

Mathematics
1 answer:
AveGali [126]3 years ago
6 0

Answer:

1 and 3

Step-by-step explanation:

I don't know how to explain. I already took algebra. Its either 1 and 3 or 1 and 4. I think its 1 and 3. GOOD LUCK

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Suppose that $2000 is placed in a savings account at an annual rate of 4.6%, compounded quarterly. Assuming that no withdrawals
LenaWriter [7]

Answer:

It will take 35.46 quarters for the account to grow to $3000.

Step-by-step explanation:

Since the annual rate is compounded quarterly, this can be calculated using the formula for calculating the future value as follows:

FV = PV * (1 + r)^n ............................ (1)

Where;

FV = future value or the amount the deposit expected to grow to = $3,000

PV = Present value or the amount place in the savings = $2,000

r = Quarterly rate = Annual rate / 4 = 4.6% / 4 = 0.046 / 4 = 0.0115

n = number of quarters it will take for the loan to grow to $3000 = ?

Substituting the values into equation (1) and solve for n, we have:

$3,000 = $2,000 * (1 + 0.0115)^n

$3,000 / $2,000 = (1.0115)^n

1.50 = (1.0115)^n

Loglinearise both sides, we have:

log(1.50) = n log(1.0115)

0.176091259055681 = n * 0.00496588710682352

n = 0.176091259055681 / 0.00496588710682352

n = 35.4601816891322

Rounding to the nearest hundredth, which also implies to rounding to 2 decimal places, we have:

n = 35.46

Since the the annual rate is compounded quarterly, it will therefore take 35.46 quarters for the account to grow to $3000.

3 0
3 years ago
Help!!! please what's is the figure​
S_A_V [24]

Hello from MrBillDoesMath!

Answer:

108 cm^2

Discussion:

The area of the logo  =

area of Trapezoid on top (I)  + area of triangle on bottom (II)

I  = (1/2) h ( b1 + b2)            h = altitude, b1, b2 = bases

  = (1/2)  6  ( 6  + 12)

  = (1/2) 6 ( 18)

  = 54

II  = (1/2) b h

   = (1/2) (12) ( 15 - 6)               => altitude of triangle = 15 - 6 NOT (1/2) 15

   =  54

I + II= 54 + 54 = 108

Thank you,

MrB

3 0
3 years ago
Read 2 more answers
H^-2g for h=3 and g=27
Alexeev081 [22]
Plug h = 3 and g = 27 into the expression:

h^{-2}g=  \dfrac{g}{h^2} = \dfrac{27}{3^2} = \dfrac{27}{9} = 3
3 0
3 years ago
PLEASE HELP ASAP I’LL MARK BRAINLIEST Find the area of the figure.
Sonbull [250]
Area of a semicircle is 1/2* πr^2
Area of a square is s^2


Square’s area: 4mm^2

The radius is 3mm
Plug into the equation

1/2* π(3^2)
1/2* π(9)

We can use 3.14 as an estimate of pi

1/2*28.26

14.13mm^2

Now just add them both

Total area 18.13mm^2
4 0
3 years ago
Solve the following system of equations.
timofeeve [1]
+8y and -8y cross out.

So the first one is 3x=15
Second one is 2x=10

x=5
Then plug x is one of the equations

2(5)-8y=10
10-8y=10

x=5
y=0
3 0
3 years ago
Read 2 more answers
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