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Blababa [14]
3 years ago
11

Please help me I am currently struggling with this please help as soon as possible

Mathematics
1 answer:
Step2247 [10]3 years ago
4 0
You strugglein on “8,9”?
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Please help i need it
Volgvan

Answer: question 1: 20 question 2: 21 question 3: 17, 19, 23

Step-by-step explanation:

8 0
3 years ago
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A manufacturer makes closed cubic containers from sheet metal. How many square centimeters of sheet metal will a 27,000 cm 3 con
dezoksy [38]

let's recall that a cube is just a rectangular prism with all equal sides, check picture below.

\bf \textit{volume of a cube}\\\\ V=s^3~~ \begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} V=&27000 \end{cases}\implies 27000=s^3\implies \sqrt[3]{27000}=s\implies 30=s \\\\[-0.35em] ~\dotfill\\\\ \textit{surface area of a cube}\\\\ SA=6s~~\begin{cases} s=&length~of\\ &a~side\\ \cline{1-2} s=&30 \end{cases}\implies SA=6(30)\implies SA=180

6 0
3 years ago
What is the product?
fredd [130]

Answer:

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}   =  \frac{2}{k + 2}

Step-by-step explanation:

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}

To solve the above, we need to follow the steps below;

4k+2 can be factorize, so that;

4k +2 = 2 (2k + 1)

k² - 4  can also be be expanded, so that;

k² - 4 = (k-2)(k+2)

Lets replace  4k +2  by  2 (2k + 1)

and

k² - 4 by  (k-2)(k+2)   in the expression  given

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}

\frac{2(2k+ 1)}{(k-2)(k+2)}   ×  \frac{k-2}{2k+1}

(2k+1) at the numerator will cancel-out (2k+1) at the denominator, also (k-2) at the numerator will cancel-out (k-2) at the denominator,

So our expression becomes;  

\frac{2}{k + 2}

Therefore, \frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}   =  \frac{2}{k + 2}

3 0
3 years ago
Read 2 more answers
What are the interest costs and other fees for using a credit card called?
BartSMP [9]

Answer:

C: Finance Charge

Step-by-step explanation:

3 0
3 years ago
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What’s the answer?!!
Grace [21]

Answer:

6x+10mm=p is the answer

brainlest plz

6 0
3 years ago
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