Please help me I am currently struggling with this please help as soon as possible

Hannah is flying a kite with a trying that is 60 feet long. If Patricia is standing directly below the kite and 16 feet away fro

Nataly_w [17]

Answer:

74.5°

Step-by-step explanation:

Hannah, the kite and Patricia form the vertices of a right-angled triangle with the hypotenuse side the length of the string L = 60 feet and adjacent side the distance between Hannah and Patricia = d = 16 feet.

Let the angle between the string and the sand be Ф.

By trigonometric ratios,

cosФ = adjacent/hypotenuse

= d/L

= 16 feet/60 feet

= 0.2667

Ф = cos⁻¹(0.2667)

= 74.53°

≅ 74.5°

So, he angle between the string and the sand is Ф = 74.5°

7 0

3 years ago

Round 0.977 to the nearest hundredth

UkoKoshka [18]

.98 since the hundredth place is higher than a five it is rounded up

5 0

3 years ago

Multiply polynomials

Burka [1]

Answer -2x^4 - 2x^3 + 22x^2 - 30x + 12

Here's your solution

=> (2x^2 - 4x + 2) - (x^2 + 3x - 6)

=> (2x^2 - 4x + 2) -x^2 - 3x + 6

=> firstly multiple whole with -x^2

=> -x^2(2x^2 - 4x + 2) = -2x^4 + 4x^3 - 2x^2

=> now with -3x

=> -3x(2x^2 - 4x + 2) = -6x^3 +12x^2 -6x

=> with 6

=> 6(2x^2 - 4x + 2) = 12x^2 - 24x + 12

=> now add all terms

=> -2x^4 - 2x^3 + 22x^2 - 30x + 12

hope it helps and your day will be full of happiness ^_^

4 0

3 years ago

What is 10 2/3 times 3?

svetlana [45]

That'd be 32 with no remainder.

5 0

3 years ago

Given: m∠EYL=72° Find: mEHL , mLVE

White raven [17]

Answer:

Part 1) The measure of arc EHL is $108\°$

Part 2) The measure of angle LVE is $54\°$

Step-by-step explanation:

step 1

Let

x-----> the measure of arc EHL

y----> the measure of arc EVL

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

so

$m$

we have

$m$

substitute

$72\°=\frac{1}{2}(y-x)$

$144\°=(y-x)$

$y=144\°+x$ ------> equation A

Remember that

$x+y=360\°$ -----> equation B ( complete circle)

substitute equation A in equation B and solve for x

$x+(144\°+x)=360\°$

$2x=360\°-144\°$

$x=216\°/2=108\°$

Find the value of y

$y=144\°+x$

$y=144\°+108\°=252\°$

therefore

The measure of arc EHL is $108\°$

The measure of arc EVL is $252\°$

step 2

Find the measure of angle LVE

we know that

The inscribed angle measures half that of the arc comprising

Let

x-----> the measure of arc EHL

$m$

we have

$x=108\°$

substitute

$m$

3 0

3 years ago