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Zigmanuir [339]
3 years ago
14

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista

nce in 1.5 h. Car B traveled 15 mph faster than Car A. How fast did Car B travel? (The formula R·T=D , where R is the rate of speed, T is the time, and D is the distance can be used.) Enter your answer for the box.
Mathematics
2 answers:
Vilka [71]3 years ago
7 0
B=60mph + A=2mph do a+b=62mph
irakobra [83]3 years ago
4 0

Answer: Car B traveled 60 mph.

Step-by-step explanation:

A= B-15

A: (B - 15)(2 hr)=D

B: (B)(1.5)=D

Since B and A traveled the same distance you can plug in 1.5B for D.

2B - 30 = 1.5B

-1.5B +30 = -1.5B

——————+30—

2(0.5B) = 2(30)

B = 60 mph

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Step-by-step explanation:

Given:

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Distance = √(x1 - x2)² + (y1 - y2)²

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Distance between JK = √64 + 1

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Distance between LJ = √4 + 49

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Distance between LJ = 7.28 unit

Perimeter of JKL = Distance between JK + Distance between KL + Distance between LJ

Perimeter of JKL = 8.06 + 7.21 + 7.28

Perimeter of JKL = 22.55 unit (Approx.)

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