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Zigmanuir [339]
2 years ago
14

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista

nce in 1.5 h. Car B traveled 15 mph faster than Car A. How fast did Car B travel? (The formula R·T=D , where R is the rate of speed, T is the time, and D is the distance can be used.) Enter your answer for the box.
Mathematics
2 answers:
Vilka [71]2 years ago
7 0
B=60mph + A=2mph do a+b=62mph
irakobra [83]2 years ago
4 0

Answer: Car B traveled 60 mph.

Step-by-step explanation:

A= B-15

A: (B - 15)(2 hr)=D

B: (B)(1.5)=D

Since B and A traveled the same distance you can plug in 1.5B for D.

2B - 30 = 1.5B

-1.5B +30 = -1.5B

——————+30—

2(0.5B) = 2(30)

B = 60 mph

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Could someone please help me with this question
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Proportional: second and third, non-proportional: first and fourth

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A bus leaves Los Angeles at 8am moving northeast at 60 mph. Three hours later, a truck leaves the same place traveling 1 2/3 tim
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Answer:

7.5 hours

Step-by-step explanation:

Using the variable 't' for time, you can set up an equation to find out how long it will take the truck to catch up to the  bus.  Since the bus is traveling at 60mph and the truck is traveling 1 2/3 times faster, we need to first find the rate of the truck:

1\frac{2}{3}=\frac{5}{3}

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Using 't' and the knowledge that they will have traveled the same distance we the truck catches up to the bus and the fact that the truck left 3 hours later:

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