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Zigmanuir [339]
2 years ago
14

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista

nce in 1.5 h. Car B traveled 15 mph faster than Car A. How fast did Car B travel? (The formula R·T=D , where R is the rate of speed, T is the time, and D is the distance can be used.) Enter your answer for the box.
Mathematics
2 answers:
Vilka [71]2 years ago
7 0
B=60mph + A=2mph do a+b=62mph
irakobra [83]2 years ago
4 0

Answer: Car B traveled 60 mph.

Step-by-step explanation:

A= B-15

A: (B - 15)(2 hr)=D

B: (B)(1.5)=D

Since B and A traveled the same distance you can plug in 1.5B for D.

2B - 30 = 1.5B

-1.5B +30 = -1.5B

——————+30—

2(0.5B) = 2(30)

B = 60 mph

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Example of use of terms:
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Now back to the given statement.
To find the original statement, we find the contrapositive of the contrapositive.
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contrapositive of 
<span>
"If an item is not worth five dimes, then it is not worth two quarters.”
is the negation of the converse, which become
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The converse of the previous statement is therefore
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In this particular case, we can also take advantage of the fact that the contrapositive is the negation of the converse.  So all we have to do is the provide the negation of each component of the contrapositive to get the converse:
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Note that the converse does NOT logically mean the same as the original statement.

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