What is a greatest common multiple

1 answer:

3 0

The greatest common multiple the the largest integer that can go into two other integers.
For example.
60 and 75. A common multiple would be five since it can got into both evenly. However, the largest common multiple would be 15, because it is the largest whole number that can go into 60 and 75.
Just in case, an integer is a whole number. No decimals.

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The length of a rectangle is 6 yards longer than its width. If the perimeter of the rectangle is 32 yd, find its area in square

ddd [48]

Let, width = x
Length = x + 6

Now, perimeter, 2(l+b) = 2(x+6+x)
2(2x+6) = 32
4x + 12 = 32
4x = 20
x = 5 &
x+6 = 5+6 = 11

As rectangle's dimensions are 11*5, it's area would be: 11 * 5 = 55 yards²

So, your final answer is 55 Yd²

Hope this helps!

8 0

3 years ago

12-2²·2=?<br><br> Brainliest

zloy xaker [14]

Answer:

it would be 4

12-4×2=12-8=4

Step-by-step explanation:

hope it helps you

4 0

2 years ago

Read 2 more answers

write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o

Alenkinab [10]

$\bf f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}\\\\
f(x)=&{{ A}} \left|{{ B }}x+{{ C}} \right|+{{ D}}
\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see,

$\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.

5 0

3 years ago

In right angle RST of cos R what is the length of RT A. 7.2 ft. B. 20 ft. C. 24 ft. D. 72 ft

andrey2020 [161]

Answer:

Step-by-step explanation:

it can be 20 ft that is what l think

6 0

2 years ago

Find the geometric mean of 2 and 3

Sav [38]

The first step in solving this problem is taking 2 and 3 and multiplying them (2 * 3 = 6) .
Now, for the second step, we will cube it. Since there are 2 numbers, we are going to use the 2nd root (2sqrt(6)) This will give us: 4.89897948557 or 5 if you would round it. This would be the Geometric Mean.

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3 years ago