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SashulF [63]
2 years ago
7

An engineering firm designs a custom hexagonal screw for a computer board. A sketch of the top of the screw is below. To the nea

rest tenth,
what is the area of the screw head?

Mathematics
1 answer:
Lunna [17]2 years ago
7 0

Given that the screw is a regular hexagon with side length 6 mm, the area of the screw is 93.5 mm^2

<h3>How can the area of the screw be found?</h3>

The area of an hexagon can be found using the following equation;

A = \mathbf{ \frac{3 \cdot \sqrt{3} }{2}  \times  {a}^{2}}

Where <em>a </em>= The side length

However the side lengths are not equal, and the figure is a composite figure with two triangles and one rectangle;

Base length of the triangles = 12

Height of the triangles = 3

Area of each triangle = 0.5 × 12 × 3 = 18

Width of the rectangle = 12

Height of the rectangle = 6

Area of the rectangle = 12 × 6 = 72

Area of the screw = 18 + 18 + 72 = 108

However taking the screw as a regular hexagon, with side length <em>a </em>= 6, we have;

A =  \frac{3 \cdot \sqrt{3} }{2}  \times  {6 \: mm}^{2} = 93.5 \: mm^2

  • The correct option is <u>D. 93.5 mm^2</u>

Learn more about finding the area of an hexagon here:

brainly.com/question/2919364

#SPJ1

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