Answer:
-3x+3
Step-by-step explanation:
The equation to the line shown is formed as follows.
It passes through the points (-6,0) and (-8,6)
The gradient of the line=Δy/Δx
=(y₂-y₁)/(x₂-x₁)
=(6-0)/(-8--6)
=6/-2
=-3
The line parallel to the line shown has the same gradient i.e -3
Therefore the line in question is
-3x+3.
Answer:
y = 17x-67
Step-by-step explanation:
The one point form of line also called slope point form is given by
where (x1, y1) is the point and m is slope
Given: (x1, y1) = (4,1) and m= 17
Substituting these values in above equation to find equation in point-slope form
(y-1)=17(x-4)
y-1 = 17x-68
y = 17x-67
the point -slope form of equation y = 17x-67
<span>Assuming the graph is y=-3(√2x)-4 and y=-3√(x-4) the transformation would be:
</span><span>The graph is compressed horizontally by a factor of 2
x=1/2x'
</span>y=-3(√2x)-4
y=-3(√x')-4 <span>
</span><span>moved left 4
x=x'-4
</span>y=-3(√x)-4
y=-3(√x'-4)-4
<span>
moved down 4
y=y'-4
</span>y=-3(√x-4)-4
y'-4=-3(√x'-4)-4
y'=-3(√x'-4)-4 +4
y'=-3(√x'-4)
Answer: C. <span>The graph is compressed horizontally by a factor of 2, moved left 4, and moved down 4.
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