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ValentinkaMS [17]
3 years ago
6

144/-12 help me asap Please

Mathematics
1 answer:
nikitadnepr [17]3 years ago
3 0
12x -12 = 144

So..

144/-12 = 12

Hope this helps
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If 3x + 6y = 7z, find x + 2y in terms of z.
o-na [289]

Answer:

Does the answer help you?

3 0
3 years ago
For what value of p will the pair of linear equations have infinitely many solutions (p-3)x + 3y = p , px+ py = 12
sleet_krkn [62]

Answer: p = 6


Step-by-step explanation:

HI !


 px + 3y - ( p-3)=0


a₁ = p , b₁ = 3 , c₁ = - (p-3)


=====================


12x + py - p=0


a₂ = 12  , b₂ = p , c₂ = -p


since , the equations have infinite solutions , 


a₁/a₂ = b₁/b₂ = c₁/c₂


p/12 = 3/p =  p-3/p



--------------------------------------


p/12 = 3/p


cross multiply ,


p² = 36


p = √36

 p = 6


for the value of p = 6 , the equations will have infinitely many solutions





5 0
3 years ago
Can you answer these please many thanks
givi [52]

Given: (a) 2(x+3)=2x+6 and (b) 4(y-3)=4y-12.

To find: The expanded form of the given expressions.

(c) 4(m+n)=4m+4n       (using a(b+c)=ab+ac)

(d) 3(5-q)=15-3q           (using a(b-c)=ab-ac)

(e) 5(2c+1)=10c+5          (using a(b+c)=ab+ac)

(f) 3(2x-5)=6x-15          (using a(b-c)=ab-ac)

(g) 7(4b-1)=28b-7          (using a(b-c)=ab-ac)

(h) 3(2x+y-5)=3((2x+y)-5)

⇒3(2x+y-5)=3(2x+y)-15         (using a(b-c)=ab-ac)

⇒3(2x+y-5)=6x+3y-15            (using a(b+c)=ab+ac)

(i) 2(6a-4b+3)=2((6a-4b)+3)

⇒2(6a-4b+3)=2(6a-4b)+6         (using a(b+c)=ab+ac)

⇒2(6a-4b+3)=12a-8b+6            (using a(b-c)=ab-ac)

(j)6(m+n+p)=6((m+n)+p)

⇒ 6(m+n+p)=6(m+n)+6p           (using a(b+c)=ab+ac)

⇒ 6(m+n+p)=6m+6n+6p            (using a(b+c)=ab+ac)

(k) y(y+2)=y^2+2y          (using a(b+c)=ab+ac)

(l) g(g-3)=g^2-3g           (using a(b-c)=ab-ac)

(m) n(4-n)=4n-n^2        (using a(b-c)=ab-ac)

(n) a(b+c)=ab+ac           (using a(b+c)=ab+ac)

(o) s(3s-4)=3s^2-4s        (using a(b-c)=ab-ac)

(p) 2x(x+5)=2x^2+10x     (using a(b+c)=ab+ac)

(q) 4y(x-3)=4xy-12y      (using a(b-c)=ab-ac)

(r) 5a(2b-5)=10ab-25a     (using a(b-c)=ab-ac)

(s) 4a(3b+2c)=12ab+8ac    (using a(b+c)=ab+ac)

(t) 5p(4p-5q)=20p^2-25pq    (using a(b-c)=ab-ac)

6 0
3 years ago
Form a polynomial function(x) with zeros: -2, multiplicity 1; 1, multiplicity 2; 5, multiplicity 3; and degree 6. Use 1 as the l
Citrus2011 [14]

Answer:

Remember, a number a is a zero of the polynomial p(x) if p(a)=0. And a has multiplicity n if the factor (x-a) appear n times in the factorization of p(x).

1. Since -2 is a zero with multiplicity 1, then (x+2) is a factor of the polynomial.

2. Since 1 is a zero with multiplicity 2, then (x-1) is a factor of the polynomial and appear 2 times.

3. Since 5 is a zero with multiplicity 3, then (x-5) is a factor of the polynomial and appear 3 times.

Then, the polynomial function with the zeros described above is

p(x)=(x+2)(x-1)^2(x-5)^3= x^6-15x^5+72x^4-78x^3-255x^2+525x-250

8 0
3 years ago
My sister needs help ( casandra0606 )
AleksandrR [38]
The formula for volume of a prism is v=(1/2bh)h so it would be
​(1/2​​ ×7.8×4)×9= 140.4
5 0
3 years ago
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