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evablogger [386]
3 years ago
14

Hey guys, I need help with this word problem. I don't just want the answer. I would like the steps please!

Mathematics
1 answer:
ASHA 777 [7]3 years ago
7 0
So, you take the equation for y given, y=0.28x+5.92. Then you substitute the values for x in, like so: 
y=0.28(2)+5.92=6.42
y=0.28(5)+5.92=7.17
y=0.28(8)+5.92=7.92
So There's your table. Next:
7.88=0.28x+5.92
x=7, so the year when admission was approximately $7.88 is year 7. 
Next, 
10.04=0.28x+5.92
x=<span>14.7142857143, which rounds to year 15. 
I hope this helps!</span>
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If a line with a slope of -2 crosses the y-axis at (0, 3), what is the equation of the line?
Karo-lina-s [1.5K]

Answer: Option D

y +2x = 3

Step-by-step explanation:

The equation of a line in the form of "slope-interception" has the following form:

y = mx + b

Where m is the slope of the line and b is the interception of the line with the y axis.

In this case we know that the line has a slope of -2. Then m = -2.

We also know that the line intercepts the axis y at the point (0, 3) therefore we know that:

b = 3.

Finally the equation of the line will be:

y = -2x + 3

If we add 2x on both sides of the equation we get:

y +2x = 3

The answer is the option D

5 0
3 years ago
Given the functions f(x)= 1/x−4 +3 and g(x)=1/x+1 +6 .
melomori [17]

ANSWER

The graph shifts 5 units left and 3 units up.

EXPLANATION

The given functions are:

f(x) =  \frac{1}{x - 4}  + 3

and

g(x) =  \frac{1}{x + 1}  + 6

We want to transform f(x) so that, it coincide with the g(x).

The required transformation is

f(x+5)+3

Let us see why this works.

f(x+5)+3 = \frac{1}{x + 5- 4}  + 3 + 3

f(x+5)+3 = \frac{1}{x + 1}  + 6 = g(x)

The transformation f(x+5)+3 will shift f(x) 5 units left and 3 units up.

The third choice is correct.

7 0
3 years ago
Read 2 more answers
What is the answer for 24-9/12
kvasek [131]
Answer= 94/4

I hope this helps you

Thank me by pressing heart ❤️
6 0
3 years ago
A report states that the mean yearly salary offer for students graduating with a degree in accounting is $48,734. Suppose that a
DENIUS [597]

Solution :

To claim to be tested is whether "the mean salary is higher than 48,734".

i.e. μ > 48,734

Therefore the null and the alternative hypothesis are

$H_0 : \mu = 48,734$

and $H_1 : \mu > 48,734$

Here, n = 50

$\bar x = 49,830$

s = 3600

We take , α = 0.05

The test statistics t is given by

$t=\frac{\bar x - \mu}{\frac{s}{\sqrt n}}$

$t=\frac{49,830 - 48,734}{\frac{3600}{\sqrt 50}}$

t = 2.15

Now the ">" sign in the $H_1$ sign indicates that the right tailed test

Now degree of freedom, df = n - 1

                                              = 50 - 1

                                              = 49

Therefore, the p value = 0.02

The observed p value is less than α = 0.05, therefore we reject $H_0$. Hence the mean salary that the accounting graduates are offered from the university is more than the average salary of 48,734 dollar.

3 0
3 years ago
PANDEMIC: How do víruses spread through a population?
soldi70 [24.7K]

Answer:

there is no table, just a list of numbers. we need a table or maybe a ss for reference

3 0
3 years ago
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