This is the answer i got!
So the waiting time for a bus has density f(t)=λe−λtf(t)=λe−λt, where λλ is the rate. To understand the rate, you know that f(t)dtf(t)dt is a probability, so λλ has units of 1/[t]1/[t]. Thus if your bus arrives rr times per hour, the rate would be λ=rλ=r. Since the expectation of an exponential distribution is 1/λ1/λ, the higher your rate, the quicker you'll see a bus, which makes sense.
So define <span><span>X=min(<span>B1</span>,<span>B2</span>)</span><span>X=min(<span>B1</span>,<span>B2</span>)</span></span>, where <span><span>B1</span><span>B1</span></span> is exponential with rate <span>33</span> and <span><span>B2</span><span>B2</span></span> has rate <span>44</span>. It's easy to show the minimum of two independent exponentials is another exponential with rate <span><span><span>λ1</span>+<span>λ2</span></span><span><span>λ1</span>+<span>λ2</span></span></span>. So you want:
<span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span><span>P(X>20 minutes)=P(X>1/3)=1−F(1/3),</span></span>
where <span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span><span>F(t)=1−<span>e<span>−t(<span>λ1</span>+<span>λ2</span>)</span></span></span></span>.
(35-21) = 14 so your answer would be 14
(7/6 x 30= 35 and 7/6 x 18= 22
3x+2y=11--------x1
7x-y=3------------x2
3x+2y=11---equ 1
14x-2y=6---equ 2
equ 1+ equ 2 will eliminate y
17x=17
x=1
then put x=1 in equ 1
3(1)+2y=11
2y=11-3
2y=8
y=8/2
y=4
Answer:
180.06
Step-by-step explanation:
We first need to sustitue x and y for the time workd on saturday and sunday :)
10.75(1.5)(4.5) + 10.75(2)(5)
Now we multpily in order!!
10.75(1.5)(4.5) + 10.75(2)(5)
72.56 + 10.75(2)(5)
72.56 + 107.50
Now we add!!
72.56 + 107.50
180.06
Your answer is 180.06 :)
Have an amazing day!!
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