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Alex
3 years ago
5

Ramon is having some friends over after a baseball game. Ramon's job is to make vegetable dip. The ingredients for the recipe ar

e given. 3/4 cup parsley, 1/3 cup will, 6/8 cup scallions, 5/8 cup buttermilk, 1/2 cup cream cheese, 1/16 cup lemon juice. Which ingredients does Ramon use the greater amount of buttermilk or cream cheese? Explain how you found your answer.
Mathematics
1 answer:
Citrus2011 [14]3 years ago
8 0

Answer:

Butter milk

Step-by-step explanation:

one half is 4/8 but the butter milk has a numerator of 5 this is why it is greater


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One root of f(x) = 2x3 9x2 7x – 6 is –3. explain how to find the factors of the polynomial.
m_a_m_a [10]
<span>We have the following polynomial:

f(x)=2x^{3}+9x^{2}+7x-6

The problem states that one root is -3. Thus, it is true that (x+3) is a factor of the polynomial. Given that this is fulfilled, it is also true that:

</span>f(x)=(x+3)Q(x) \therefore Q(x)=\frac{f(x)}{x+3} \\ \\ where \ Q(x) \ has \ a \ degree \ of \ 2<span>

We can find Q(x) by applying Ruffini's rule, thus:

</span>\ \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ 9 \ \ \ \ \ \ \ \ 7 \ \ \ \ \ \ -6  \\ -3 \\ \rule{50mm}{0.1mm} \\ \ {} \ \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ 3 \ \ \ \ \ -2 \ \ \ \ \ \ \ \ 0<span>

Therefore:

Q(x)=2x^{2}+3x-2

The roots of this polynomial can be get as follows:

x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \rightarrow x_{12}=\frac{-3\pm\sqrt{3^2-4(2)(-2)}}{2(2)}\\x_{1}=\frac{1}{2};\ x_{2}=-2

These are the roots along with -3. Finally, the factored polynomial can be written as follows:

f(x)=(x+3)(x+2)(2x-1)</span>
4 0
4 years ago
Read 2 more answers
Number 9 and 10. Say which one you r doing plzzz
Dahasolnce [82]
Try this first :) Let me know what you come up with :)

3 0
3 years ago
For a moving object, the force acting on the object varles directly with the object's acceleration. When a force of 25 N acts on
Radda [10]

\Huge{\underline{\underline{\mathfrak{Answer \colon}}}}

According to the Question,

\large{\sf{ f \propto \: a}}

<h3>From the Question,</h3>

  • Initial Acceleration,a = 5 m/s²

  • Force at a = 5 m/s²,f = 25 N

  • Final Acceleration,A = 9 m/s²

<h3>To find</h3>

Force exerted on the object at a = 9 m/s²

We Know that,

\huge{\boxed{ \boxed{ \sf{f = ma}}}}

Firstly,we need to find the mass of the object

Thus,

\sf{m =  \frac{f}{a} } \\  \\  \implies \:  \sf{m =  \frac{25}{5} } \\  \\  \huge{ \implies \:  \sf{m = 5 \: kg}}

Now,

\sf{F = mA} \\  \\  \implies \:  \sf{F = (5)(9)} \\  \\  \huge{ \implies \:  \sf{F = 45 \: N}}

7 0
3 years ago
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AlladinOne [14]
No, the answers are incorrect.
When reflected over the y-axis, if the x is positive, then it becomes negative, but if the x is negative, then it becomes positive. Also, the y will not change.
The answer should be 
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Y prime: (10,4)
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5 0
3 years ago
A:
Montano1993 [528]

Step-by-step explanation:

it is solved directly by using the formula

4 0
3 years ago
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