Question

Wilt and bill, two basketball players, are having a free throw shooting contest. wilt is known to make 75% of his free throws, and bill is known to hit 85% of his free throws. each of them takes 50 shots. assuming that the shots are independent, what is the probability that bill hits a higher percentage of his shots than wilt?

Answer 1

Use standard deviation

$\sqrt{(0.75 * 0.25) / 50 + (0.85 * 0.15) / 50) }$ =0.0794
 P(z> (0-0.1) / 0.0794)
 P(z> -1.26) = 0.8962