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Alekssandra [29.7K]
3 years ago
11

Suppose a normal distribution has a mean of 50 and a standard deviation of

Mathematics
2 answers:
grandymaker [24]3 years ago
7 0

Then standardize the two scores

48 and 52

to be able to consult the table.

The formula for changing a raw score x into a z score is

Z=X−μσ.

For this problem, X is normal with

μ=50 and σ=5.

So, by symmetry of the standard normal curve,

P(48<X<52)

=P(48−50<X−50<52−50)

=P(48−505<X−505<52−505)

=P(−25<Z<25)

=P(−.40<Z<.40)

=P(Z<.40)−P(Z<−.40)

=P(Z<.40)−P(Z>.40)

=P(Z<.40)−(1−P(Z<.40))

=2P(Z<.40)−1

=2(.6554)−1

=1.3108−1

=.3108≈.31

=31%.

hoa [83]3 years ago
5 0

Answer:

27.8% I think

Step-by-step explanation:

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Answer:

a) 5

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d) 10

Step-by-step explanation:

a) 7-2=5

b) 2(7)+3(2)

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= 20

c) 2(7)(3)= 28

d) (7-2)^2

= (14-4)

= 10

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2 years ago
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Simora [160]

(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.

(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?

On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:

50 ≤ score ≤ 60   ==>   50-60

60 < score ≤ 70   ==>   60-70

70 < score ≤ 80   ==>   70-80

80 < score ≤ 90   ==>   80-90

90 < score ≤ 100   ==>   90-100

Then a student who scored a 60 should be added to the 50-60 category.

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The heights of a group of boys and girls at a local middle school are shown on the dot plots below. 2 dot plots with number line
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Answer:sushi love sushi sushi is life and life is sushi

Step-by-step explanation:

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3 years ago
find a parametric representation of the solution set of the linear equation. (enter your answer as a comma-separated list of equ
Ostrovityanka [42]

To represent the solution set of a linear equation parametrically, we introduce other parameters like s and t for the free variables.

Every linear equation has n - 1 free variables where n is the number of variables.

For x + y + z = 2, we have 3 variables and 3 - 1 = 2 free variables.

First, let y and z be the free variables, we first solve the linear equation for x to get:

x = 2 - y - z

Therefore , the parametric representation of the solution set is given by :

x = 2 - s -t

y = s

z = t

Learn more about The linear Equation at:

brainly.com/question/17748588

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2 years ago
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