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kow [346]
3 years ago
14

Tariq designed the pool shown. The owner of the pool has one square cover to use. Find the area of the space that needs to be co

vered. (The four corners are squares.)
The area that needs to be covered is


___ ft2.

Mathematics
1 answer:
Aleks [24]3 years ago
3 0

Step 1: Find the total area. Since it is a square all the sides are 12 ft so multiply 12 by 12

12 x 12 = 144

^^^This is the total area including the area around the pool. We just need the are of the pool

Step 2: Outside of the pool there are four little 2 ft by 2 ft squares that aren't part of pool, and therefore won't need to be covered. The area of these 2 ft by 2 ft square is 4ft (2 times 2 is 4). Since there are 4 of these squares we multiply 4 by 4 to get 16. This means that 16 ft of the 144 ft we found previously are not part of the pool and we must subtract 16 from 144 to get the total pool area

144 - 16 = 128

This means that the area of the pool is 128 ft

Hope this helped and made sense! Let me know!

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What is the y-intercept of 6x + 12y = 60
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Answer:

it means when x =0

so 6*0+12y=60

12y=60

y=5

Step-by-step explanation:

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5

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Select the slope of the equation y-7= -4(x+8)
stiks02 [169]

Answer:

Slope is -4

Step-by-step explanation:

y-7=-4(x+8)

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y=-4x-32+7

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3 years ago
Solve using elimination 6x + 2y = -8 3x - 2y = -19
Jobisdone [24]

Answer:

x=-3, y=5

Step-by-step explanation:

6x + 2y = -8   3x - 2y = -19

Add the two equations together to eliminate y

6x + 2y = -8

3x - 2y = -19

------------------------

9x        = -27

Divide each side by 9

9x/9 = -27/9

x = -3

Now we find y

6x + 2y = -8

6(-3) +2y = -8

-18+2y = -8

Add 18 to each side

-18+18 +2y = -8+18

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Divide by 2

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3 0
2 years ago
(Sec. 8.4) In a sample of 165 students at an Australian university that introduced the use of plagiarism-detection software in a
marusya05 [52]

Answer:

z=\frac{0.667 -0.5}{\sqrt{\frac{0.5(1-0.5)}{165}}}=4.29  

The p value for this case is given by:

p_v =P(z>4.29)=8.93x10^{-6}  

Since the p value is lower than the significance level we have enough evidence to conclude that the true proportion is significantly higher than 0.5 at 5% of significance.

Step-by-step explanation:

Information given

n=165 represent the random sample selected

55 represent the students indicated a belief that such software unfairly targets students

X =165-55= 110 represent students who NOT belief that such software unfairly targets students

\hat p=\frac{110}{165}=0.667 estimated proportion of  students who NOT belief that such software unfairly targets students

p_o=0.5 is the value that we want to check

\alpha=0.05 represent the significance level

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to check if the majority of students at the university do not believe that it unfairly targets them, and the system of hypothesis are:

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

The statistic for this case is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

After replace we got:

z=\frac{0.667 -0.5}{\sqrt{\frac{0.5(1-0.5)}{165}}}=4.29  

The p value for this case is given by:

p_v =P(z>4.29)=8.93x10^{-6}  

Since the p value is lower than the significance level we have enough evidence to conclude that the true proportion is significantly higher than 0.5 at 5% of significance.

7 0
3 years ago
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