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Ipatiy [6.2K]
3 years ago
7

Explain and give me the answer please

Mathematics
1 answer:
777dan777 [17]3 years ago
7 0

Answer:

154 because we multiply the 11in and 14 in to get 154 inches so h = 154 inches

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If the following two triangles are similar, find X.<br><br> Show work please
anastassius [24]
The similarity ratio is 20/10 = 2, so x can be found as:

10/2 = x = 5
7 0
3 years ago
(2/5) Help me with this problem, please.
lana [24]

You divided in the wrong order. The resulting image always goes first then the preimage is afterward.

scale factor = (new)/(old) = 10/8 = 1.25

<h3>Answer is choice B</h3>

The scale factor is larger than 1, so this means we have an enlargement going on.

4 0
3 years ago
In ∆XYZ, m∠X = 152, y = 15, and z = 19. Find side x and the measure of angle Y to the nearest tenth
solong [7]

The measure of the side x is approximately 33 and the measure of angle Y is approximately 12.321°.

<h3>How to find a missing angle in a triangle by law of sine and law of cosine</h3>

In this problem we must apply the law of cosine and the law of sine to determine the angle Y:

<h3>Law of cosine</h3>

x = \sqrt{y^{2}+z^{2}-2\cdot y\cdot z\cdot \cos X}

x = \sqrt{15^{2}+19^{2}-2\cdot (15)\cdot (19)\cdot \cos 152^{\circ}}

x \approx 33

<h3>Law of sine</h3>

\frac{\sin Y}{y} = \frac{\sin X}{x}

Y = \sin^{-1}\left(\frac{y}{x}\cdot \sin X \right)

Y = \sin^{-1}\left(\frac{15}{33}\cdot \sin 152^{\circ} \right)

Y \approx 12.321^{\circ}

The measure of the side x is approximately 33 and the measure of angle Y is approximately 12.321°. \blacksquare

To learn more on triangles, we kindly invite to check this verified question: brainly.com/question/25813512

7 0
2 years ago
Square root of 48841​
agasfer [191]

Answer:

The square root of 48841 is 221.

Step-by-step explanation:

If you multiply 221 by 221, then you get 48841. So the square root is 48841. Hope this helped! :D

5 0
3 years ago
I need help ASAP . Brainlist will be given !!
dolphi86 [110]

Answer:

5,4 and 4,4

Step-by-step explanation:

3 0
3 years ago
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