Hi there!
Find the area of the parallelogram using the formula:
A = b × h
Thus:
A = 7 × 5 = 35 units²
PLZZZZZZZ HELP IM BEING TIMED!!!!!!!!!!!
1 answer:
Answer:
<h2>D. 26.5 mm</h2>Step-by-step explanation:
A median of trapezoid is a line segment between the midpoints of the legs of a trapezoid (<em>look at the picture)</em>.
The formula of a length of a median of a trapezoid:
<em>a, b</em><em> - bases</em>
<em />
We have <em>a = AB = 19mm</em>, and <em>b = DC = 34 mm</em>. Substitute:
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Refer to the diagram shown below.
When x = 30 ft, the cable is at 15 ft, therefore y(30) = 15.
That is,
a(30 - h)² + k = 15 (1)
Also, because the distance between the supports is 90 ft, therefore
y(0) = 6 ft, and y(90) = 6 ft
That is,
a(-h)² + k = 6 (2)
a(90 - h)² + k = 6 (3)
From (2) and (3), obtain
a(90 - h)² = ah²
90² - 180h + h² = h²
180h = 90²
h = 45 ft.
From (1) and (2), obtain
225a + k = 15
2025a + k = 6
Therefore
1800a = -9
a = - 0.005
k = 15 - 225(-0.005) = 16.125 ft
Answer:
The equation for the cable is
y = - 0.005(x - 45)² + 16.125
A graph of the solution verifies that the solution is correct.
When x = 30 ft, the cable is at 15 ft, therefore y(30) = 15.
That is,
a(30 - h)² + k = 15 (1)
Also, because the distance between the supports is 90 ft, therefore
y(0) = 6 ft, and y(90) = 6 ft
That is,
a(-h)² + k = 6 (2)
a(90 - h)² + k = 6 (3)
From (2) and (3), obtain
a(90 - h)² = ah²
90² - 180h + h² = h²
180h = 90²
h = 45 ft.
From (1) and (2), obtain
225a + k = 15
2025a + k = 6
Therefore
1800a = -9
a = - 0.005
k = 15 - 225(-0.005) = 16.125 ft
Answer:
The equation for the cable is
y = - 0.005(x - 45)² + 16.125
A graph of the solution verifies that the solution is correct.
Answer:
Step-by-step explanation:
Area of Rectangle = bh = 16 ft x 18 ft = 288
Area of Triangle = 1/2 bh = 1/2 x (16-12) ft x (6) ft x 2 (There's 2 triangles) = 24
24 ft^2 + 288 ft^2 = 312 ft^2